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Mark Scheme (Results)January 2019Pearson Edexcel International Advanced Level InMechanics M1 (WME01/01)

Edexcel and BTEC QualificationsEdexcel and BTEC qualifications are awarded by Pearson, the UK’s largest awarding body. Weprovide a wide range of qualifications including academic, vocational, occupational andspecific programmes for employers. For further information visit our qualifications websitesat www.edexcel.com or www.btec.co.uk. Alternatively, you can get in touch with us using thedetails on our contact us page at www.edexcel.com/contactus.Pearson: helping people progress, everywherePearson aspires to be the world’s leading learning company. Our aim is to help everyoneprogress in their lives through education. We believe in every kind of learning, for all kinds ofpeople, wherever they are in the world. We’ve been involved in education for over 150 years,and by working across 70 countries, in 100 languages, we have built an internationalreputation for our commitment to high standards and raising achievement throughinnovation in education. Find out more about how we can help you and your students at:www.pearson.com/ukJanuary 2019Publications Code WME01 01 1901 MSAll the material in this publication is copyright Pearson Education Ltd 2019

General Marking Guidance Allcandidatestreatment.mustreceivethesameExaminers must mark the firstcandidate in exactly the same way as they markthe last. Mark schemes should be applied positively.Candidates must be rewarded for what theyhave shown they can do rather than penalisedfor omissions. Examiners should mark according to the markscheme not according to their perception ofwhere the grade boundaries may lie. There is no ceiling on achievement. All marks onthe mark scheme should be used appropriately. All the marks on the mark scheme are designedto be awarded. Examiners should always awardfull marks if deserved, i.e. if the answer matchesthe mark scheme. Examiners should also beprepared to award zero marks if the candidate’sresponse is not worthy of credit according tothe mark scheme. Where some judgement is required, markschemes will provide the principles by whichmarks will be awarded and exemplification maybe limited. When examiners are in doubt regarding theapplication of the mark scheme to a candidate’sresponse, the team leader must be consulted. Crossed out work should be marked UNLESSthe candidate has replaced it with an alternativeresponse.

PEARSON EDEXCEL IAL MATHEMATICSGeneral Instructions for Marking1. The total number of marks for the paper is 752. The Edexcel Mathematics mark schemes use the following types of marks: M marks: Method marks are awarded for ‘knowing a method and attempting toapply it’, unless otherwise indicated. A marks: Accuracy marks can only be awarded if the relevant method (M) markshave been earned. B marks are unconditional accuracy marks (independent of M marks) Marks should not be subdivided.3. AbbreviationsThese are some of the traditional marking abbreviations that will appear in themark schemes. bod – benefit of doubt ft – follow through the symbol cao – correct answer only cso - correct solution only. There must be no errors in this part of the questionto obtain this mark isw – ignore subsequent working awrt – answers which round to SC: special case oe – or equivalent (and appropriate) d or dep – dependent indep – independent dp decimal places sf significant figures The answer is printed on the paper or ag- answer given will be used for correct ftor d The second mark is dependent on gaining the first mark

4. All A marks are ‘correct answer only’ (cao.), unless shown, for example, as A1 ftto indicate that previous wrong working is to be followed through. After a misreadhowever, the subsequent A marks affected are treated as A ft, but manifestly absurdanswers should never be awarded A marks.5. For misreading which does not alter the character of a question or materiallysimplify it, deduct two from any A or B marks gained, in that part of the questionaffected.6. If a candidate makes more than one attempt at any question: If all but one attempt is crossed out, mark the attempt which is NOT crossedout. If either all attempts are crossed out or none are crossed out, mark all theattempts and score the highest single attempt.7. Ignore wrong working or incorrect statements following a correct answer.

General Principles for Mechanics Marking(But note that specific mark schemes may sometimes override these general principles) Rules for M marks: correct no. of terms; dimensionally correct; all terms that need resolving (i.e.multiplied by cos or sin) are resolved. Omission or extra g in a resolution is an accuracy error not method error. Omission of mass from a resolution is a method error. Omission of a length from a moments equation is a method error. Omission of units or incorrect units is not (usually) counted as an accuracy error. DM indicates a dependent method mark i.e. one that can only be awarded if a previous specifiedmethod mark has been awarded. Any numerical answer which comes from use of g 9.8 should be given to 2 or 3 SF. Use of g 9.81 should be penalised once per (complete) question.N.B. Over-accuracy or under-accuracy of correct answers should only be penalised once per completequestion. However, premature approximation should be penalised every time it occurs. Marks must be entered in the same order as they appear on the mark scheme. In all cases, if the candidate clearly labels their working under a particular part of a question i.e. (a) or(b) or (c), then that working can only score marks for that part of the question. Accept column vectors in all cases. Misreads – if a misread does not alter the character of a question or materially simplify it, deduct twofrom any A or B marks gained, bearing in mind that after a misread, the subsequent A marks affectedare treated as A ft Mechanics AbbreviationsM(A) Taking moments about A.N2LNewton’s Second Law (Equation of Motion)NELNewton’s Experimental Law (Newton’s Law of Impact)HLHooke’s LawSHM Simple harmonic motionPCLMPrinciple of conservation of linear momentumRHS, LHSRight hand side, left hand side.

QuestionNumber1(i)SchemeMarksM1 A1A1(ii)3u 3u )2Magnitude 9muM1 A1I 3m( 2u u )Magnitude 9muM1 A1I 2m(OR:1(i)A1NotesM1 for CLM with correct no. of terms to give an equation in one unknown. Allowconsistent extra g’s and/or cancelled m’s. Condone sign errors(They may obtain this equation by finding the impulse on each and eliminating theimpulse – apply the same criteria, including condone sign errors)First A1 for a correct unsimplified equation. Allow: 6mu 3mu 2m.(ii)A13u 3mv2Second A1 for 2u (must be positive)(N.B. If all terms in the CLM are given the same sign, this leads to 2u M1A0A0)M1 for dimensionally correct Impulse-momentum equation with consistent use of 2m or3m (i.e. M0 if g included or m omitted.)I m(v u ) whenN.B. Mark the actual equation not the formula (some candidates use the direction has been reversed)First A1 for a correct unsimplified equationSecond A1 for 9mu (must be positive)6

QuestionNumber2(a)SchemeMarksM1A1A1M1 A1(b)(3)A1DM1M1 A1A1M1M1A1Notes2(a)M1 for any trig ratio using 6 and 7:2(b)A1 for a correct angle from their correct equation e.g. 49o, 41o, 139o, 131o, .A1 for 319o caoFirst M1 for attempt at use of r4 r0 4 v for either A or B6767tan θ or : sinθ or cos θ or 222766 76 72i's and j's must be collected at some stagei's and j's must be collected at some stageFirst A1 for ( 4i 11j)Second A1 for ( 8 4 p )i (9 8 p ) jSecond DM1, dependent on first M1, for finding the difference between their twor4 vectors (must be an attempt to subtract both i and j components)Third M1 for equating the i cpt and j cpt of their difference (M0 if no difference) to givean equation in p only. oee.g.(4 4 p ) ( )1 (2 8 p ) ( )1Third A1 for a correct equation in p onlyFourth A1 for a correct value of pFourth M1 for using their p value to obtain a velocity vector for BFifth M1 for finding the magnitude of their v B (N.B. This M mark is available, even iftheir v B does not have the correct form)Fifth A1 for5oe or21.1 or better(10)13

QuestionNumber3(a)Scheme(b)(c)(2)M1 A1(2)A1(ii)(b)M1 A1DM1(c) (i)(a)MarksA1NotesM1 for equation of motion for the person only, with usual rules, condone sign errors, andwith at least one value (560 or 1.4) substituted. Credit given for this equation only if itappears in (a).A1 for a correct equationM1 for equation of motion for the lift only, with usual rules, condone sign errors, and withat least one value (2800, 560 or 1.4) substituted. Credit given for this equation only if itappears in (b).A1 for a correct equationHence:DM1, dependent on appropriate previous M mark, for solving one of their equations,wherever it appears, for either m or MOtherwise:DM1, dependent on appropriate previous M mark, for solving one of their equationsand/or the whole system equation, wherever they appear, for either m or MN.B. There are no marks available for the whole system equationFirst A1 for m 50Second A1 for M 200(3) 7

QuestionNumber4(a)(b)(c)SchemeM1 A2Mass of the box is concentrated at the point Q oeM ( R ) , 3Mg 30g 0.5 2.5 g 2 40 g 2M 4(a)70, 23 or better3NotesM1 for moments about R to give an equation in x (or another unknown distance) only(i.e. M0 if reaction at P is non-zero) Correct no. of terms, dimensionally correctA2 for a correct equation in x only (allow consistent omission of g) -1 each errorAlternative: Instead of M ( R ) , they may write down 2 equations and eliminate thenormal reaction at R, N R , to obtain an equation in a distance only :( )N R 40 g 30 g 2.5 gPossible equations:M ( P ) , 40 gx 30 g 2.5 2.5 g 5 3N RM ( Q ) , 40 g (5 x) 30 g 2.5 2NRM ( G ) , 40 g (2.5 x) 0.5 N R 2.5 g 2.5Equations must have correct no. of terms and be dimensionally correct but M0 if reactionat P is non-zeroThird A1 for(b)(c)Marks13m oe Allow 3.3 m4B1 for mass or weight of box acts at Q but B0 if extra wrong answersM1 for moments about R to give an equation in M only(i.e. M0 if reaction at P is non-zero) Correct no. of terms, dimensionally correctA2 for a correct equation in M only (allow consistent omission of g) -1 each errorAlternative: Instead of M ( R ) , they may write down 2 equations and eliminate thenormal reaction at R, S R , to obtain an equation in M only :( )S R 40 g 30 g 2.5 g MgPossible equations:3S RM ( P ) , 42.5 g 5 30 g 2.5 2S RM ( Q ) , Mg 5 30 g 2.5 M ( G ) , Mg 2.5 0.5S R 42.5 g 2.5Equations must have correct no. of terms and be dimensionally correct but M0 if reactionat P is non-zeroThird A1 for70oe or 23 or better3Accept 24A1B1M1 A2A1(4)(1)(4)9

QuestionNumber5.SchemeMarks3.52 ( sin245 ) 2 2 3.5 ( sin245 ) cos 45o 2.5PM 3.5 2 tan 45o 1.5 OR PB 1.543 ;cos α ;sin α255ooOR α 37 or (90 α ) 53o (at least 2SF)M1 tan αA1TP cos α TQ cos 45o 6gM1 A2TP sin α TQ cos 45oM1 A1 TP30 g 42 N; TQ 36 or 35.6 N7-1 eeDM1 A1; A110NotesFirst M1 for finding the length of PM or PBFirst A1 for a correct trig ratio for α or (90o α ) or a correct value for α or (90o α )Do not penalise accuracy here if their final answers for the tensions are correct.N.B. If they assume the tensions are the same , no further marks availableIf they think α 30 or 60 or., they could get all 5 resolving marks as a value of α isnot required but if α 45, only M marks available. However, if α and 45 areinterchanged in the resolving equations - no marks available for resolvingSecond M1 for resolving vertically with usual rulesSecond/Third A1’s for a correct equation, ( α does not need to be substituted) -1 each errorThird M1 for resolving horizontally with usual rulesFourth A1 for a correct equation ( α does not need to be substituted but if it is , followthrough on their value)Fourth DM1, dependent on all THREE previous M marks, for solving for either tensionFifth A1 for TP Allow 42.0Units not neededSixth A1 for TQUnits not neededAlternative, using Triangle of Forces/Lami’s Theorem, for middle 5 marks.TP6g osin 45sin(45o α )TQ6gsin(180 α ) sin(45o α )TQTP osin 45sin(180o α )o ORORN.B. Treat omission of g as one errorTQsin(180 α )o 6gsin(45o α )TP6g osin 45sin(45o α )M1 A2ORM1 A1-1 ee

QuestionNumber6(a)SchemeMarksB1 ShapeB1 Figs. and V(2)(b) 4500(c)(270 180)V2ORV 20114500 60V 180V 30V22(T T 60)1 20 2250 OR60.20 (T 60).20 225022T 142.5 s(d)T1 1 604 15 1 3 T2 270 30 OR 240 30 4 4 262.5Notes6(a)6(b)6(c)6(d)First B1 for a trapezium (not to scale) starting and finishing on the t-axis but B0 if solidvertical lines includedSecond B1 for 3 figs. (60, 270 and use of 30 with a delineator or 240) and V.270 can be implied by 3 correct delineatorsM1 for a complete method to produce an equation, in V only, with the correct structure i.e.one trapeziumor two triangles rectangleor triangle trapeziumor trapezium triangleor rectangle – two triangles 4500 (allow 4.5 for the M mark)(M0 if a single suvat equation is used)First A1 for a correct unsimplified equationSecond A1 for V 20M1 for a complete method to produce an equation, in ONE variable e.g. t wheret (T – 60), with the correct structurei.e. one trapeziumor triangle rectangleor rectangle – triangle 2250 (allow 2.25 for the M mark)(M0 if a single suvat equation is used)First and second A1’s for a correct unsimplified equation ft on their 20 -1 each errorThird A1 for 142.5 (s) cao Accept 143.First M1 for a complete method to give an equation in T1 onlyM1 A1A1(3)M1 A2 ftA1(4)M1A1M1 A1A1(5)14

First A1 for 15 (independent of V so allow even if their V is wrong)Second M1 for a complete method to give an equation in T2 onlySecond A1 for a correct equationThird A1 for 262.5 (independent of V so allow even if their V is wrong) Accept 263N.B. Accept T1 262.5 and T2 15

QuestionNumber7(a)SchemeFor B,For B,S 3mg cos α3mg sin α T F1 3maM1 A1M1 A2For A,For A,R mgT F2 maB1M1 A1 F1(b)(c)Marks S ; F21315RM1DM1Solving for T3mgT or 5.88m5Constant tension throughout the string.(180o α )R 2T cos21( 2T sin α ) (2Tcos 63.4o )23mg5 2 556mg 5 (5.3m or 5.26m)25A1(11)B1(1)M1 A1DM1A116OR:R (T T cos α ) 2 (T sin α ) 2 or R (T 2 T 2 2T 2 cos αSubstitute their expression for T (MUST be in terms of m) and a correct value of α6mg 5(5.3m or 5.26m) 257(a)(b)(c)(4)NotesN.B. Use of sin(4/5) or similar, treat as an A error but allow recoveryFirst M1 for resolving perp to the plane , with usual rulesFirst A1 for a correct equationSecond M1 for equation of motion parallel to the inclined plane, with usual rulesSecond and Third A1’s for a correct equation -1 each errorB1 caoThird M1 for equation of motion horizontally, with usual rulesFourth A1 for a correct equationFourth M1 for using ‘ F µ R ’ correctly twiceFifth DM1, dependent on all M marks, for solving for T in terms of m onlyFifth A1 caoN.B. Either equation of motion can be replaced by the whole system equation:3mg sin α F1 F2 4ma (M1A2 or M1A1 as appropriate)Penalise extra wrong answersFirst M1 for attempt at correct expression for R in terms of T and α with usual rules i.e.condone cos/sin confusion but must be using the correct angle (can be in terms of α )M1A1DM1A1

Special Case: Allow max M1A1DM0A0 if m is lost from their T but expression for Ris otherwise correct.First A1 for a correct expression for R in terms of T and αSecond DM1 for substituting in their expression for T and a correct value for α but mustbe in terms of mSecond A1 for a correct answer (any equivalent surd form)Pearson Education Limited. Registered company number 872828with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom

Mar 07, 2019 · 2. The Edexcel Mathematics mark schemes use the following types of marks: M marks: Method marks are awarded for ‘knowing a method and attempting to apply it’, unless otherwise indicated. A marks: Accuracy marks can only be a

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