UNIT-III Bipolar Junction Transistor Bipolar (junction .

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www.jntuworld.comEDC UNIT-3Question&answerUNIT-III Bipolar Junction Transistor1.Explain the construction and working of BJT.A bipolar (junction) transistor (BJT) is a three-terminal electronic device constructed ofdoped semiconductor material and may be used in amplifying or switching applications. Bipolartransistors are so named because their operation involves both electrons and holes. Charge flowin a BJT is due to bidirectional diffusion of charge carriers across a junction between two regionsof different charge concentrations. An NPN transistor can be considered as two diodes with ashared anode. In typical operation, the base-emitter junction is forward biased and the base–collector junction is reverse biased. In an NPN transistor, for example, when a positive voltage isapplied to the base–emitter junction, the equilibrium between thermally generated carriers andthe repelling electric field of the depletion region becomes unbalanced, allowing thermallyexcited electrons to inject into the base region. These electrons wander (or "diffuse") through thebase from the region of high concentration near the emitter towards the region of lowconcentration near the collector. The electrons in the base are called minority carriers becausethe base is doped p-type which would make holes the majority carrier in the base.To minimize the percentage of carriers that recombine before reaching the collector–basejunction, the transistor's base region must be thin enough that carriers can diffuse across it inmuch less time than the semiconductor's minority carrier lifetime. In particular, the thickness ofthe base must be much less than the diffusion length of the electrons. The collector–base junctionis reverse-biased, and so little electron injection occurs from the collector to the base, butelectrons that diffuse through the base towards the collector are swept into the collector by theelectric field in the depletion region of the collector–base junction. The thin shared base andasymmetric collector–emitter doping is what differentiates a bipolar transistor from two separateand oppositely biased diodes connected in series.Transistor 'alpha' and 'beta'The proportion of electrons able to cross the base and reach the collector is a measure of the BJTefficiency. The heavy doping of the emitter region and light doping of the base region causemany more electrons to be injected from the emitter into the base than holes to be injected fromthe base into the emitter. The common-emitter current gain is represented by βF or hfe; it isapproximately the ratio of the DC collector current to the DC base current in forward-activeregion. It is typically greater than 100 for small-signal transistors but can be smaller in transistorsdesigned for high-power applications. Another important parameter is the common-base currentgain, αF. The common-base current gain is approximately the gain of current from emitter tocollector in the forward-active region. This ratio usually has a value close to unity; between 0.98and 0.998. Alpha and beta are more precisely related by the following identities mPage 1

www.jntuworld.comEDC UNIT-3Question&answerFig Simplified cross section of a planar NPN bipolar junction transistorA BJT consists of three differently doped semiconductor regions, the emitter region, the baseregion and the collector region. These regions are, respectively, p type, n type and p type in aPNP, and n type, p type and n type in a NPN transistor. Each semiconductor region is connectedto a terminal, appropriately labeled: emitter (E), base (B) and collector (C).The base is physically located between the emitter and the collector and is made from lightlydoped, high resistivity material. The collector surrounds the emitter region, making it almostimpossible for the electrons injected into the base region to escape being collected, thus makingthe resulting value of α very close to unity, and so, giving the transistor a large β. A cross sectionview of a BJT indicates that the collector–base junction has a much larger area than the emitter–base junction.Small changes in the voltage applied across the base–emitter terminals causes the current thatflows between the emitter and the collector to change significantly. This effect can be used toamplify the input voltage or current. BJTs can be thought of as voltage-controlled current source,but are more simply characterized as current-controlled current sources, or current amplifiers,due to the low impedance at the base.NPNThe symbol of an NPN Bipolar Junction Transistor.GRIET-ECEG.Surekhawww.jntuworld.comPage 2

www.jntuworld.comEDC UNIT-3Question&answerNPN is one of the two types of bipolar transistors, in which the letters "N" (negative) and "P"(positive) refer to the majority charge carriers inside the different regions of the transistor. Mostbipolar transistors used today are NPN, because electron mobility is higher than hole mobility insemiconductors, allowing greater currents and faster operation. NPN transistors consist of a layerof P-doped semiconductor (the "base") between two N-doped layers. A small current entering thebase in common-emitter mode is amplified in the collector output. In other terms, an NPNtransistor is "on" when its base is pulled high relative to the emitter. The arrow in the NPNtransistor symbol is on the emitter leg and points in the direction of the conventional current flowwhen the device is in forward active mode.PNPThe other type of BJT is the PNP with the letters "P" and "N" referring to the majority chargecarriers inside the different regions of the transistor.The symbol of a PNP Bipolar Junction Transistor.PNP transistors consist of a layer of N-doped semiconductor between two layers of P-dopedmaterial. A small current leaving the base in common-emitter mode is amplified in the collectoroutput. In other terms, a PNP transistor is "on" when its base is pulled low relative to the emitter.The arrow in the PNP transistor symbol is on the emitter leg and points in the direction of theconventional current flow when the device is in forward active mode.Regions of operationApplied voltagesModeE B CForward activeE B CSaturationE B CCut-offBipolar transistors have five distinct regions of operation, defined by BJT junction biases.The modes of operation can be described in terms of the applied voltages (this descriptionapplies to NPN tranistors; polarities are reversed for PNP ge 3

www.jntuworld.comEDC UNIT-3Question&answerForward active: base higher than emitter, collector higher than base (in this mode thecollector current is proportional to base current by β F).Saturation: base higher than emitter, but collector is not higher than base.Cut-Off: base lower than emitter, but collector is higher than base. It means the transistoris not letting conventional current to go through collector to emitter.In terms of junction biasing: ('reverse biased base–collector junction' means Vbc 0 for NPN,opposite for PNP)Forward-active (or simply, active): The base–emitter junction is forward biased and thebase–collector junction is reverse biased. Most bipolar transistors are designed to affordthe greatest common-emitter current gain, βF, in forward-active mode. If this is the case,the collector–emitter current is approximately proportional to the base current, but manytimes larger, for small base current variations.Saturation: With both junctions forward-biased, a BJT is in saturation mode andfacilitates high current conduction from the emitter to the collector. This modecorresponds to a logical "on", or a closed switch.Cutoff: In cutoff, biasing conditions opposite of saturation (both junctions reversebiased) are present. There is very little current, which corresponds to a logical "off", or anopen switch.Bipolar Transistor e 4

www.jntuworld.comEDC UNIT-3Question&answerThe construction and circuit symbols for both the NPN and PNP bipolar transistor are shownabove with the arrow in the circuit symbol always showing the direction of conventional currentflow between the base terminal and its emitter terminal, with the direction of the arrow pointingfrom the positive P-type region to the negative N-type region, exactly the same as for thestandard diode symbol.2. Explain CB configuration with the help of input and output characteristics.There are basically three possible ways to connect a Bipolar Transistor within an electroniccircuit with each method of connection responding differently to its input signal as the staticcharacteristics of the transistor vary with each circuit arrangement.1. Common Base Configuration - has Voltage Gain but no Current Gain.2. Common Emitter Configuration - has both Current and Voltage Gain.3. Common Collector Configuration - has Current Gain but no Voltage Gain.The Common Base Configuration.As its name suggests, in the Common Base or Grounded Base configuration, the BASEconnection is common to both the input signal and the output signal with the input signal beingapplied between the base and the emitter terminals. The corresponding output signal is takenfrom between the base and the collector terminals as shown with the base terminal grounded orconnected to a fixed reference voltage point. The input current flowing into the emitter is quitelarge as its the sum of both the base current and collector current respectively therefore, thecollector current output is less than the emitter current input resulting in a Current Gain for thistype of circuit of less than "1", or in other words it "Attenuates" the signal.The Common Base Amplifier CircuitThis type of amplifier configuration is a non-inverting voltage amplifier circuit, in that the signalvoltages Vin and Vout are In-Phase. This type of arrangement is not very common due to itsunusually high voltage gain characteristics. Its Output characteristics represent that of a forwardbiased diode while the Input characteristics represent that of an illuminated photo-diode. Alsothis type of configuration has a high ratio of Output to Input resistance or more importantly"Load" resistance (RL) to "Input" resistance (Rin) giving it a value of "Resistance Gain". Then theVoltage Gain for a common base can therefore be given as:GRIET-ECEG.Surekhawww.jntuworld.comPage 5

www.jntuworld.comEDC UNIT-3Question&answerCommon Base Voltage GainThe Common Base circuit is generally only used in single stage amplifier circuits such asmicrophone pre-amplifier or RF radio amplifiers due to its very good high frequency response.Input/ Output CharacteristicsCommon-Base:o Input characteristics: The EB junction is essentially the same as a forward biaseddiode, therefore the current-voltage characteristics is essentially the same as thatof a diode:Also the collector-base voltage V CB 0 helpsenhance the current IE to some extent.Output characteristics:As the CB junction is reverse biased, the current I C depends totally on IE. When IE 0,IC ICB0 isthe current caused by the minority carriers crossing the pn-junction. This is similar to the diodecurrent-voltage characteristics seen before, except both axes are reversed (rotated 180 degrees),as both voltage ICB and current IC are defined in the opposite directions. When I E is increasedIC αIE ICBO is increased correspondingly. Higher VCB can slightly increase α and there by IC.AsIC IE CB configuration does not have current-amplification effect.GRIET-ECEG.Surekhawww.jntuworld.comPage 6

www.jntuworld.comEDC UNIT-3Question&answer3. Explain CE configuration with the help of input and output characteristics.The Common Emitter Configuration.In the Common Emitter or Grounded Emitter configuration, the input signal is applied betweenthe base, while the output is taken from between the collector and the emitter as shown. Thistype of configuration is the most commonly used circuit for transistor based amplifiers andwhich represents the "normal" method of connection. The common emitter amplifierconfiguration produces the highest current and power gain of all the three bipolar transistorconfigurations. This is mainly because the input impedance is LOW as it is connected to aforward-biased junction, while the output impedance is HIGH as it is taken from a reverse-biasedjunction.The Common Emitter Amplifier CircuitIn this type of configuration, the current flowing out of the transistor must be equal to thecurrents flowing into the transistor as the emitter current is given as Ie Ic Ib. Also, as the loadresistance (RL) is connected in series with the collector, the Current gain of the Common EmitterTransistor Amplifier is quite large as it is the ratio of Ic/Ib and is given the symbol of Beta, (β).Since the relationship between these three currents is determined by the transistor itself, anysmall change in the base current will result in a large change in the collector current. Then, smallchanges in base current will thus control the current in the Emitter/Collector circuit.By combining the expressions for both Alpha, α and Beta, β the mathematical relationshipbetween these parameters and therefore the current gain of the amplifier can be given as:GRIET-ECEG.Surekhawww.jntuworld.comPage 7

www.jntuworld.comEDC UNIT-3Question&answerWhere: "Ic" is the current flowing into the collector terminal, "Ib" is the current flowing into thebase terminal and "Ie" is the current flowing out of the emitter terminal.Then to summarise, this type of bipolar transistor configuration has a greater input impedance,Current and Power gain than that of the common Base configuration but its Voltage gain is muchlower. The common emitter is an inverting amplifier circuit resulting in the output signal being180o out of phase with the input voltage signal.Common-Emitter:Input characteristics:Same as in the case of common-base configuration, the EB junction of the commonemitter configuration can also be considered as a forward biased diode, the currentvoltage characteristics is similar to that of a diode:The collector-emitter voltage VCE has little effect on IB.Output characteristics:The CB junction is reverse biased, the currentdepends on the current IB. When IB 0,IC ICEO the current caused by the minority carriers crossingthe pn-junctions. When IB is increased IC is correspondingly increased by β.GRIET-ECEG.Surekhawww.jntuworld.comPage 8

www.jntuworld.comEDC UNIT-3Question&answerVarious parameters of a transistor change as functions of temperature. For example, βincreases along with temperature.4. Explain CC configuration with the help of input and output characteristics.The Common Collector Configuration.In the Common Collector or Grounded Collector configuration, the collector is now commonand the input signal is connected to the Base, while the output is taken from the Emitter load asshown. This type of configuration is commonly known as a Voltage Follower or EmitterFollower circuit. The Emitter follower configuration is very useful for impedance matchingapplications because of the very high input impedance, in the region of hundreds of thousands ofOhms, and it has relatively low output impedance.The Common Collector Amplifier CircuitThe Common Emitter configuration has a current gain equal to the β value of the transistor itself.In the common collector configuration the load resistance is situated in series with the emitter soits current is equal to that of the emitter current. As the emitter current is the combination of thecollector and base currents combined, the load resistance in this type of amplifier configurationalso has both the collector current and the input current of the base flowing through it. Then thecurrent gain of the circuit is given as:GRIET-ECEG.Surekhawww.jntuworld.comPage 9

www.jntuworld.comEDC UNIT-3Question&answerThis type of bipolar transistor configuration is a non-inverting amplifier circuit in that the signalvoltages of Vin and Vout are "In-Phase". It has a voltage gain that is always less than "1" (unity).The load resistance of the common collector amplifier configuration receives both the base andcollector currents giving a large current gain (as with the Common Emitter configuration)therefore, providing good current amplification with very little voltage gain.5.Give the Comparisions between CB,CE,CC configurations.with the characteristics of the different transistor configurations given in the following table:CommonBaseInput impedanceLowOutput impedanceVery HighPhase Angle0oVoltage GainHighCurrent GainLowPower GainLow6. What is the Relation between , & ?CommonEmitterMediumHigh180oMediumMediumVery HighCharacteristicRELATION BETWEEN ,a)&We know IE IC IB, But IC IE & IE IBIE - IE Dividing both sides byGRIET-ECECommonCollectorHighLow0oLowHighMediumIc ,IBor IB IBICIE(1 ICIE.IE (1 - ))G.Surekhawww.jntuworld.comPage 10

www.jntuworld.comEDC IEIBIEICICIB1 OR I E IC.11or 1 IC I B11IE, Substituting IB IE - IC.IB(c)IEIEIC ,by diving Numerator & Denominator on R.H.S, byIE / IEIE / IEIC / I EPutting the value of IE.11/ 1.11111(or )1111(or )1117. Explain early effect or base width modulation in CB configuration.EARLY EFFECT OR BASE WIDTH MODULATION.As VCC made to increase the reverse bias, the space charge width between collector andbase tends to increase. This results in decrease of effective width of the base. This dependence ofbase width on collector voltage is known as „Early Effect‟. This decrease of effective base widthhas three ge 11

www.jntuworld.comEDC UNIT-3(i)Question&answerThere is less chance of recombination in base region and Ic increases causing toincrease with increase in V CB.The charge gradient is increased within the base and current of minority carriesinjected across emitter junction increases.For extremely large VCB, the effective base width becomes zero causing voltagebreaks down in the transistor. This phenomenon is called the “Punch through” effect.(ii)(iii)Problems1.In common base connection IE 1mA, IC 0.95 mA calculate value of IB.IB IE – IC 1 – 0.95 0.05mA.2.In a CB configuration current amplification factor is 0.90 and emitter current is 1mA.Determine base current. 0.9, IE 1mAIC;IEIC .IE 0.9 x 1 0.9mAIB IE – IC3. 1 – 0.9 0.1mA.A BJT has IB 10 A, .99 and ICBO 1 A what is collector current.IC IB (1 ) I CBOB IC 99 x 10 (1 99)110.991 0.990.990.0199 990 100 1090 A 1.09 mA.GRIET-ECEG.Surekhawww.jntuworld.comPage 12

www.jntuworld.comEDC UNIT-34.Question&answerA transistor operating in CB configuration has I C 2.98mA, IE 3.0mA andIco 0.01mA. What current will flow in collector circuit of that transistor whenconnected in CE configuration and base current is 30 A.Given :In CBIC 2.98mA,In CE IB 30 A0.991 0.991IC5. IE 3.0mAIC ? IC 2.983.00.99ICO 0.01mA.IB.99990.01IB ( 1) Ico. 99 x 30 x 10-6 (100)0.01 x 10-3 2.97 x 10-3 1 x 10-3 3.97mAGiven an NPN transistor for which 0.98, Ico 2 A IEO 1.6 A. A CE configurationis used and VCC 12V and RC 4.0K. What is the min. base current required in orderthat transistor enter in to saturation region.Given 0.98, ICO ICB 2 A,IEO ICEO 1.6 A.VCC 12 V, VCE VCC 12V,RL 4.0K IB ? (In saturation)Solution:Where Transistor is in saturation VCE 0.2 (Assumed)VRL 12 – 0.2 11.8 Volts.IcVRLRL11.84 1032.95 1032.95mAWe knowGRIET-ECEG.Surekhawww.jntuworld.comPage 13

www.jntuworld.comEDC UNIT-3Question&answerIc IB ( 1) ICBO0.981 0.9812.95 x 10-3 49.980.0249IB (49 1) 2 x 10-62950 A 49IB 100 A (2950 – 100) A49IBIB 6.28504958.16 ACalculate the values of IE, dc and dc for a transistor with Ic 13 A, IB 200mA, ICBO 6 A. Also determine the new level of Ic which will result in reducing I B 100mA.Givena. Ic 13 A IB 200mA ICBO 6 Ab.a. 2850 Adc ?dc ?find Ic, when IB 100 mAWhen IB 200mAas Ic IE ?Ic cannot be 13 A.x IB.Assume Ic 13 AmperesThendc IC 13/200 x 103 65IBIE IC IB or IE 13 0.2 Amperes. 13.2 AmperesWe can also use the formulae I EWhich will also result Icdcb.IC GRIET-ECEICIEdc. IB1313.211I CBO11IB,13.2 Amperes.0.985 65 x 200 x 10-3 6.5 AmperesG.Surekhawww.jntuworld.comPage 14

www.jntuworld.comEDC UNIT-3Question&answer7. A transistor operating in CB configuration has I c 2.98 mA ,IE- 3.00mA and Ico 0.01mA.What current will flow in the collector circuit of the transistor when connected in CE configurat-ion with base current of 30 A.Given Ic 2.98 mAIc If IB 30 A,IB ( 1) ICO and2.983.00.99Ic ?0.991 0.991Ico 0.01 mAICIE,1IE 3 mA99Ic 99 x 30 x 10-6 (99 1) x 0.01 x 10-3 3970 A 3.97 mA.8. The reverse saturation current in a transistor is 8 A. If the transistor common base currentgain is 0.979, calculate the collector and emitter current for 40 A base current.Given ICO ICBO 8 AIEIE11 dICBOIC & IE for IB 40 A1147.62 8 106IB ;111 0.979147.62 40 106 0.97947.622285 1062285 AIc IE – IB 2285 – 40 2245 A.9.GivenGiven an NPN transistor for which 0.98, ICO 2 A and IEO 1.6 A. A commonemitter connection is used and VCC 12V and RL 4.0K. what is the minimum basecurrent required in order that transistor enter into saturation region. 0.98ICO 2 AIB for Icsat ?IEO 1.6 AVCC 12VRL 4.0 K.When the transistor is in saturation Ic I csat and VCE of ideal transistor 0 volts.I csatIBIBGRIET-ECEVccRLIc124000and3 104913mA0.981 0.984930.061mAOr61 A.G.Surekhawww.jntuworld.comPage 15

www.jntuworld.comEDC UNIT-3Question&answer10.The current gain of a transistor in CE circuit is 49. Calculate CE gain and find base currentwhere the emitter current is 3mA.Given 49IE ( 1) IBGRIET-ECETo findor ?IBIE1IB for IE 3mA.3 10 31 49G.Surekhawww.jntuworld.com60 APage 16

A bipolar (junction) transistor (BJT) is a three-terminal electronic device constructed of doped semiconductor material and may be used in amplifying or switching applications. Bipolar transistors are so named because their

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