Unit 4 Take Home Proofs - Teachers.Henrico Webserver

2y ago
41 Views
2 Downloads
363.50 KB
9 Pages
Last View : 1m ago
Last Download : 3m ago
Upload by : Luis Wallis
Transcription

Name: Period: Date: ID: ACongruent Triangles Quiz - HonorsMultiple ChoiceIdentify the choice that best completes the statement or answers the question.1. (1 point) Given: ΔABE ΔDBC. (The two TRIANGLES arecongruent.) Why is AEB DCB ?A) ASAB) AASC) CPCTCD) SASE) HLF) SSSG) SSA2. (1 point) In the diagram below, LN ON . What additional information isneeded to prove that ΔMNL is congruent to ΔPNO by ASA?A) MN PNB) L OC) M PD) LM OPShort Answer3. (2 points) What is wrong with the following diagram? (Answer withcomplete sentences, using appropriate geometric language.)1

Name:4. (1 point) Given ABC ID: AXYZ, AB 15 , AC 30 , YZ 25 , andXY 5x 20 , find x.5. (3 points) The two triangles are congruent as suggested by their appearance. Thediagrams are not to scale. Find the values of the variables b, d, and e.b d e Use the given information to label the diagram and decide whether the trianglesare congruent. Then name the congruence postulate or theorem you used. Namethe congruent triangles, if any. If they are not congruent (or can’t be shown tobe congruent), write, “cannot be determined.” (Don’t fill in the blanks!)6. (3 points) Given A E and AC EC.ΔABC Δ by (postulate or theorem)7. (3 points) Given: FEG HEG and FE HEΔEFG Δ by (postulate or theorem)2

Name:ID: A8. (3 points) Given: LB MB and m ALB 90 and m AMB 90 .ΔALB Δ by (postulate or theorem)9. (2 points) Given: M and B are right angles, and MZ Ä BQΔMZQ Δ by (postulate or theorem)10. (3 points) Given: HFS IFS and IS HSΔIFS Δ by (postulate or theorem)11. (3 points) Given: WT Ä AH and T HΔWHA Δ by (postulate or theorem)3

Name:ID: A12. (3 points) Given: B is the midpoint of DQΔZDB Δ by (postulate or theorem)13. (3 points) Given: BAD BCD and BD bisects angle ABC.ΔBDA Δ by (postulate or theorem)14. (3 points) Given: RT QT and AT ST TQS by (postulate or theorem)15. (3 points) Given: CE DF and CF DE CFE by (postulate or theorem)4

Name:ID: AEssay16. (6 points) Given: B is the midpoint of AD, and B is the midpoint of EC.Prove: E C17. (6 points) Given: AE Ä DC and AE DCProve: AB DB18. (6 points) Given: RT QT and AT STProve: RA QS19. (6 points) Given: QAR and RSQ are right angles, and RS QAProve: RA QS5

Name:ID: A 20. (1 point) CB bisects ACD and AB bisects CAD. The measure of CBA is 100 degrees. Find x m E. (Hint: Let a m CABand c m ACB.)6

ID: ACongruent Triangles Quiz - HonorsAnswer SectionMULTIPLE CHOICE1. ANS: C2. ANS: BSTA: G.5STA: G.5SHORT ANSWER3. ANS:The triangles are congruent by ASA, but AE DC. Both are not possible.4. ANS:7STA: G.55. ANS:606.7.8.9.10.11.STA: VA G.5a VA G.5bANS:ΔABC ΔEDC by ASAANS:EHG, SASANS:ΔALB ΔAMB by HL.ANS:ΔMZQ ΔBQZ by AASANS:cannot be determined (SSA)ANS:WTA by AAS1

ID: A12. ANS:ΔZDB ΔLQB by SSS.13. ANS:AAS14. ANS:ΔTQS ΔTRA by SAS15. ANS:ΔCFE ΔDEF by SSSESSAY16. ANS:reasons:given(S)defn midpoint(A) vertical angles theoremgiven(S)defn midpointcongruent triangles by SAS.CPCTC17. ANS:given(A)alt. int angles thm(S) given(A)alt. int angles thmcongruent triangles by ASA (or use vertical angles theorem and AAS)CPCTC2

ID: A18. ANS:given(S)given(A) T T (reflexive property of )(S)givencongruent triangles by SASCPCTC19. ANS: QAR and RSQ are right angles (given)ΔQAR and ΔRSQ are right triangles. (defn right triangle)(H) RQ QR (reflexive property of )(L) RS QA (given)congruent triangles by HLCPCTC20. ANS:Let a m CAB m BAELet c m ACB m BCDa c 100 180 (triangle sum theorem on triangle ABC)a c 80 (subtraction property)2a 2c x 180(triangle sum theorem on triangle AEC)2(a c) x 180 (distributive property)2(80) x 180 (substitution property)x 20 (subtraction property)3

Identify the choice that best completes the statement or answers the question. 1. (1 point) Given: ΔABE DBC. (The two TRIANGLES are congruent.) Why is AEB DCB? A) ASA C) CPCTC E) HL G) SSA B) AAS D) SAS F) SSS 2. (1 point) In the diagram below, LN ON. What additional inf

Related Documents:

Research on Logic Puzzles and Math Proofs Week 2 – 3 Each student is to gather 2-3 logic puzzles and 2 mathematical proofs. After studying the solutions of the selected logic puzzles and the proofs, the student submits a paper that Cullinane, A Transition to Mathematics with Proofs Logical Reasoning, pages 69-98 Nocon &Nocon,

Summary. The John James Audubon Drawings and Proofs consist of drawings, colored proofs, and uncolored proofs used to . some cases, they were made using a grid or camera lucida, which projected a reduced image onto paper. In other cases, Audubon himself created new drawings based on the originals or of birds

Trigonometry Unit 4 Unit 4 WB Unit 4 Unit 4 5 Free Particle Interactions: Weight and Friction Unit 5 Unit 5 ZA-Chapter 3 pp. 39-57 pp. 103-106 WB Unit 5 Unit 5 6 Constant Force Particle: Acceleration Unit 6 Unit 6 and ZA-Chapter 3 pp. 57-72 WB Unit 6 Parts C&B 6 Constant Force Particle: Acceleration Unit 6 Unit 6 and WB Unit 6 Unit 6

Unit B - Congruent Triangles Overview This unit focuses on triangle classifications and proving triangles congruent. Proof is a very important concept throughout the unit. Students should become fluent in completing proofs by the end of this unit by seeing the patterns and structure within proofs.

There are some recent auctions related work using non-interactive proofs and other cryptography protocols. This mentioned work discuss auctions in Smart contract settings in Blockchain. For example the article in [8], it is provided an application design short zero-knowledge proofs t

I discovered almost all the material in this monograph by computer exper-imentation, and then later on found rigorous proofs. Most of the proofs here are traditional, but the proofs do rely on 12 computer calculations. These calculations a

that integrates correctness proofs of assembly programs with game-playing proofs of provable security. We demonstrate the usability of our approach using the Blum-Blum-Shub (BBS) pseudorandom number generator, for which a MIPS implementation for smartcards is shown

are easily one-shot. However, in the lattice setting, the situation is much more complicated, and, to the best of our knowledge, there is no one-shot witness extraction technique for non-linear relations. 1.1 Related work { Lattice-based zero-knowledge proofs In being one-shot proofs, the most rele