MARK SCHEME For The June 2004 Question Papers 0580/0581 .
UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONSInternational General Certificate of Secondary EducationMARK SCHEME for the June 2004 question papers0580/0581 MATHEMATICS0580/01, 0581/01Paper 1 (Core), maximum raw mark 560580/02, 0581/02Paper 2 (Extended), maximum raw mark 700580/03, 0581/03Paper 3 (Core), maximum raw mark 1040580/04, 0581/04Paper 4 (Extended), maximum raw mark 130These mark schemes are published as an aid to teachers and students, to indicate the requirementsof the examination. They show the basis on which Examiners were initially instructed to award marks.They do not indicate the details of the discussions that took place at an Examiners’ meeting beforemarking began. Any substantial changes to the mark scheme that arose from these discussions willbe recorded in the published Report on the Examination.All Examiners are instructed that alternative correct answers and unexpected approaches incandidates’ scripts must be given marks that fairly reflect the relevant knowledge and skillsdemonstrated.Mark schemes must be read in conjunction with the question papers and the Report on theExamination. CIE will not enter into discussion or correspondence in connection with these mark schemes.CIE is publishing the mark schemes for the June 2004 question papers for most IGCSE and GCEAdvanced Level syllabuses.
Grade thresholds taken for Syllabus 0580/0581 (Mathematics) in the June 2004 examination.maximummarkavailableminimum mark required for grade:ACEFComponent 156-412823Component 270583826-Component 3104-775039Component 4130935737-The threshold (minimum mark) for B is set halfway between those for Grades A and C.The threshold (minimum mark) for D is set halfway between those for Grades C and E.The threshold (minimum mark) for G is set as many marks below the F threshold as the Ethreshold is above it.Grade A* does not exist at the level of an individual component. University of Cambridge International Examinations 2004
TYPES OF MARKMost of the marks (those without prefixes, and ‘B’ marks) are given for accurate results,drawings or statements. M marks are given for a correct method. B marks are given for a correct statement or step. A marks are given for an accurate answer following a correct e.SCs.o.i.wwwww*Anything rounding toBenefit of the doubt has been given to the candidateCorrect answer only (i.e. no ‘follow through’)Each error or omissionFollow throughOr equivalentSpecial caseSeen or impliedWithout workingWithout wrong workingWork followed through after an error: no further error madeWork followed through and another error foundIndicates that it is necessary to look in the working followinga wrong answer University of Cambridge International Examinations 2004
June 2004INTERNATIONAL GCSEMARK SCHEMEMAXIMUM MARK: 56SYLLABUS/COMPONENT: 0580/01, 0581/01MATHEMATICSPaper 1 (Core)
Page 112339842(a)(b)4Mark SchemeMATHEMATICS – JUNE 2004(a)(b)34 final answer7100 final answer111Syllabus0580/0581Ignore any or no units after answer. Allow 84200cm.149311154.5(0)2M1 for 18 x 25 or 450 or 4m 50cm seen(18:450 and 18:4.5 also indicate M1)64 12 or2M1 for92or184or 4 42Paper194x2(1)seen.Allow SC1 for 4.5 or 4 12 oe seen with incomplete ordecimal working.( 49 or 2(1)oe or 2.25 0.5)Answer only, no working, is 0.1 for each answerSC1 for both values correct but wrong way round.7141.5, 142.5282x( 2y – 3z)2M1 for 2( 2xy – 3xz) orx( 4y – 6z ) or 2x(wrong expression)Allow omitted last bracket.9190.48 or 190.47 or 1902M1 for 200 1.05, implied by 190.( .)Not allow 190.5 or 190.4 or 190.00 for 2 marks(a) and (b) reversed–no marks10(a)(b)021111(a)110 212(a)(b)(a)(i)30200 40111(a)(ii)5f.t.1(b)5.6B or 2nd – dependent on M1,M1132.65 or2.649( .)318131415B1 for Q 35 s.o.i.(can be on diagram)70 seen implies B1.Only f.t. for simple mental calculation. E.g. 220 40 5.5or 200 30 6 or 7 or 6 23 or 6.6 or 6.66 etcM1 for a correct method for 1 bottle, implied by figs 615 or652 seen or figs 1625 or 153 seen.M1(dep) for a complete correct method with consistent units.(Implied by a correct pair of values seen.Alt. Method completely correct is M2M1 for sin 32 h5M1 (dep) for h 5sin 32 (2.6. implies M2provided no obvious scale drawing, which is zero) Othermethods can be split similarly.From grads 2.409 or radians 2.757 implies M213 University of Cambridge International Examinations 2004
Page 21619Syllabus0580/0581Paper1(a)132M1 for –3 16 seen(b)y – a or y – a oebb bAllow a – y–bBar Chart2M1 for a correct step, for clearly dividing by b or y – a seen.4S1 correct scale and equal width bars. (Lost for vertical linesdrawn)B2 all bars correct height or B1 for any 2 bars correct height.Dots or line graph is B0.L1 correct labels.(a) 4.5(0)2M1 for 50 x ( 0.25 or 25) or 12.5(0) or 1250 seen,or 0.25 – 8 50 (0.09)or 25 – 800 50 ( 9)(b) *56.25 or 56 or 56.3 or 56.22f.t.M1 for their (a)/8 x 100 ortheir profit for 1 orange 100their cost for 1 orange(a)2826 to 2828 or28302M1 for π x 30(b) *226.(080) to226.(240) or 226.(4 )2f.t.M1 for his (a) 80 s.o.i. or correct f.t. answer seen in cubiccentimetres.1718Mark SchemeMATHEMATICS – JUNE 200422or π 0.3 and method not spoilt.162021M1 for 31 5 or 31 – 5 or x – 1.25 7.754M1 for 4y – 20 36 or y – 5 9 or better.(a)92(b)142(a)00 15 or 12 15amIgnore am added to00 157 h 30minAllow 7 12 or 7.5 hours1Allow a clear time in words. E.g. 15 minutes after midnight.Not 12 15 or 24 151f.t.f.t. their (a)749.(33 .) f.t.3f.t.B1 for their 7.5 or 7 12 or their 450 minutes and(finally) multiplied by 60 used.M1 for 5620/their time (independent of B1)(f.t. dependent on B1 and M1)[Watch for 5620 7.3 769.(86 )implies B0 M1.](b)(i) *(b)(ii) *9 University of Cambridge International Examinations 2004
June 2004INTERNATIONAL GCSEMARK SCHEMEMAXIMUM MARK: 70SYLLABUS/COMPONENT: 0580/02, 0581/02MATHEMATICSPaper 2 (Extended)
Page 1Mark SchemeMATHEMATICS – JUNE 2004QuestionMark SchemeNumber13h 20m210.930.53 0.52 0.51 20p2456789101124637571516112*22*1, 12*41(b)41(a)(b)450800008 x 104x 8 y 150, 5, 3 c e k (a)2*11 3*1, 1, 13*M1 for 0.25, 0.7. and 0.125 seen matchedB11or p202M1 x/4 6 or x – 32 -8 seenB1 correct but reversedB1 for one of -7/8, -1/8, -14/16, -2/16, -0.875,-0.125Not 90 or1turn4M1 for 3000 x 7.5 x 2/1008 x 104M1 double and add/subtract consistently A1A1 or M1 rearrange and substitute correctlyR1, R1 for any 2 correct steps moving e, k or Allow d2 (c – e)/k to score R2 as a single step1Arc must not continue outside rectangle.Radius of arc 4 cm 1 mm. Ignore shading1x π x 424(b)12.62*M1 for(a)(b)4a ca – c or –c a3*11M1 Area factor or ratio 9 M1 LSF 3(c) 2*M1 A0 for answers simplifying to these seen2*2*M1 2 arcs centre B and D, line drawn A1M1 construction arcs on AD and CD and centrethese for the bisector, line drawn A1Dependent on at least 1 1 in part (a)SC1, SC1 If accurate and no construction arcsM1 782 832M1 for finding one angle by trigonometrycorrectlyM1 for clearly identifying bearing angleScale drawing and answers with no workingscore zero17111a - c or (a c)222118(a)(b)114(0)47 cao2*3*19(a)111(b)x 22*M1(c)32*M1 for explicit g(1) or g-1(x) (a)(b)3(2x – y)(2x y)(i) x2 – 6x 9(ii) p 3 q 122*2B1 (6x – 3y)(2x y) o.e.M1 correct methodB1, B120Paper2Notes(a)1213146385Syllabus0580/05812( x 1) 12 University of Cambridge International Examinations 2004x 12
Page 221Mark SchemeMATHEMATICS – JUNE 2004Syllabus0580/0581Paper2(a)1.82M1 convincing gradient calculation or use ofa (v – u)/t(b)4502*M1 for 20 x 18 (c)133*M1 for finding total area under graph((b) 135) dep M1 for 451x 10 x 182If the vertical scale is consistentlymisread then M4 A0 is available22(a)(b)(c)BA or (iii) 38 0 0 38 4/38 6 / 38 1 4 6 or 38 5 2 5/38 2 / 38 TOTAL2*M1 checking order of all 4 matrices correctly2M1 either column or row correct10.158 2 / 19 3 / 19 0.105 or 5 / 38 1/ 19 0.132 0.0526 70 University of Cambridge International Examinations 2004
June 2004INTERNATIONAL GCSEMARK SCHEMEMAXIMUM MARK: 103SYLLABUS/COMPONENT: 0580/03, 0581/03MATHEMATICSPaper 3 (Core)
Page 1Mark SchemeMATHEMATICS – JUNE 2004FINAL MARK 0581Paper3June 2004Marks CommentsTotal1ii492iii462bi20 60 160 80 40 (360)2iicorrect pie chart ( 2 )2correct labelsL1iii a4/9 oe1iii b1/3 oe2M1 for clear evidence ofrankingM1 for total/10, allowingerrors in additionM1 for evidence of 4 oe seenor SC1 for 3 or 4 correct5 sectors only. Any order.Or SC1 for 3 or 4 correct or ftcorrect4 or 5 correct or ft correctallow (0).44 ,44. .%, butnot 0.4M1 for their((D E)/T) fromtheir table. Can be implied.For both parts 1 once forincorrect notation eg 4 out of9, 1:3, 4 in 9 etc0.3 ww is zero13132a9161181 ft for 3 their bi (not strict ft)(0).62M1 for 3 0.2302 d(0).022M1 for their bii/ci (not strict ft)or 2 3/0.2M1 for 2 0.1 0.1 oeSC1 for fig 2e4.8(0) 9(.00) 14.4(0)2.1(0)30.3(0)4B1 for each1 ft from 4 total costsbiiiciii14143a7 8 4 13B2 for 3 correct orB1 for 2 correct University of Cambridge International Examinations 2004
Page 2bMark SchemeMATHEMATICS – JUNE 2004Syllabus0580/058113 correct or ft correctpoints ( 1/2 a square)P3 P2 for 11 or 12 correct orP1 for 7 to 10 correctCorrect curve caoC1reasonable parabola shape, nostraight line segments, pointedmaximum etcc 2.7 to 2.92.7 to 2.911d 1511ecorrect line drawn 3 x 32f22g 3111Paper3M1 for incomplete line orfreehand line or both their(in)correct points correctlyplottedM1 for attempt at y/ x fromtheir straight line graph 1 if y values given as well17174a1201b702M1 for t 2t 75 75 360 oe3t and 210 implies M1ci130 oe (eg 180 50)2M1 for angle sum oftriangle( 180) usedii100 oe (eg360 100 160)2M1 for angle sum ofquadrilateral( 360) usediiix 70 and y 303 M1 for attempted eliminationof one variable (be generous)A1 for each answer. no ft.correct answers reversedimplies M1A110105abi(0).21Tangent and radiusmentioned1or described. University of Cambridge International Examinations 2004
Page 3Mark SchemeMATHEMATICS – JUNE 2004Syllabus0580/0581ii8 cao1iiiart 1.783M1 for (their) 82 7.82 oeM1(indep) for square rootindicated or used1.77 ww implies M2.1.8 ww is zeroiv6.9 (2 sig figs only)3 ft for answer correct to 2 sigfigs (not strict ft)(3.9 theirbiii)or M1 for 0.5 7.8 their biii A1 for answer to more than 2sig figsPaper396aiiibiiitranslation caoB1or translated10 2B1B1rotation or turnM1centre the origin oeA1( ) 90 (anticlockwise)A1allow quarter turn for M1A1correct reflectiondrawn2SC1 for reflection in x-axiscorrect enlargementdrawn2SC1 for scale factor 2, wrongcentre 1 for incorrect notation or adescriptionSC1 for both answers correctbut inverted10197aipentagon1ii5402iii108 cao1ii110 or x 70 or y 20completionart 50.2M1A12may be on diagramBeware of circular argumentsM1 for tan( 1) and 120/100iii120(.2)1 ft for 70 their biibiM1 for 3 180, or 5 180 360or (180 360/5) 5 or 6 90 University of Cambridge International Examinations 2004
Page 4ivMark SchemeMATHEMATICS – JUNE 20043001 Syllabus0580/0581Paper3ft for 180 their biii 1 for answers reversed10108aiiiiiibcde6 ( 0.1)1012 73 to 76both lines drawn ( 0.1cm)12mediator drawn( 0.1cm and 1o ) withtwo pairs of arcscomplete circle, radius4 ( 0.1) cm drawn,centre CL marked correctly2 SC1 for 10n where n is aninteger. (ft 60/their ai)B1 for each line. Ignore anycurves at ends, lines must be atleast 5 cm long. Allow dottedetcB1 for correct line with no arcsor correct arcs with no line2SC1 for incomplete circle1be convinced119ai121ii201iii2n 2 oe2bia201bibii254812iii1002M1 for 2n k where k is anintegerM1 for 12 seen (as diagramno.)M1 for 10 seen1021TOTAL MARKS104 University of Cambridge International Examinations 2004
June 2004INTERNATIONAL GCSEMARK SCHEMEMAXIMUM MARK: 130SYLLABUS/COMPONENT: 0580/04, 0581/04MATHEMATICSPaper 4 (Extended)
Page Mark SchemeMATHEMATICS – JUNE 2004Syllabus0580/0581Paper460 x 120o.e.100( ) 132c.a.o.their(a)(i) x 100o.e.120110(%) Final answer, but may beexplained using 10.M1Implied by 72 seen and not spoilt.A1M1ww2159.10 (x100)o.e.their 86( ) 185c.a.o.o.e.156 x 5216948(cm)c.a.o.11 x 36o.e.2019.8(km)c.a.o.36 x 23o.e.2414(km)c.a.o.p 9 q 3 r 9Scales correctTheir 8 points plotted correctly (1mm)Reasonable curve through all 8 of theirpoints ( 1mm tolerance)Tangent drawn at x 1 on curve 3.5to 2.5 Condone fractionsM1u 6.33 or betterv 6Their 6 points plotted correctly (1mm)Reasonable curve through all 6 of theirpoints (1mm tolerance)their (a)(i) x 100120Sc1 for 10 or their extra % or their(a)(i) 120x100120Allow any statement that equates 159.10 with 86%provided it is not contradicted later.ww2 x o.e.Alt. Method 156156 169x 52ww2Method not spoilt by also doing 9 x 3620ww2 Condone 19.8:16.216.2:19.8 is M1A0 ftA1 A1M1A1M1A1M1A11 1 1S1 P2 C1 T1B21 1P3 C1 ww212Must be seen. No feedback from graph.x from 3 to 4. y to accommodate their values.P1 for 6 or 7 of their points correct.Condone ruled line for x 3 to 4 or –3 to –2.ft provided correct shape maintained.Or a parallel line drawn.If B2 not scored, give B1 for 2.5 to 3.5 after M1.Allow u 19/3P2 for 5 correct ( ).P1 for 4 correct ( ).Condone ruled line for x 2 to 3.ft provided correct shape maintainedx2 x 3 6 x3/3o.e.32to x 3x 3x 27 02.3 to 2.7c.a.o.Median 36 to 37 (cm)IQR19 to 21 (cm)Evidence of using 146 (approx)32 to 33 (cm)275 to 281E1B1B1B2M1A1B2350 303365 350B1B1Midpoints 5,15,25,35,45,55,65 fx attempted(13065) fx / 36535.8 or 36 or 35.79 wwwM1M1*M1A1At least 6 correct s.o.i.Dep. on first M1 or using midpoints 0.5Dep. on second M1*www4[35.79452055]B1M1A1ISW subsequent rounding to 3 or 5 once seen.eg a factor of 1.5 used constructively.2.9 (cm)Evidence of dividing by 304.9 (cm)c.a.oo.ec.a.o.At least 1 intermediate step and no errors seen.Not coordinates18Sc1 for 45.5 to 46.5 or 25.5 to 26.5 seen.ww2Sc1 for 84 to 90 seen University of Cambridge International Examinations 200416
Page 2Mark SchemeMATHEMATICS – JUNE 2004Syllabus0580/0581Paper4(AC2 ) 9.52 11.12 2x9.5x11.1cos70M2Allow M1 for 9.52 11.12 AC2 cos702 x 9.5 x 11.1square root of correct combination(141.3279 ) or 11.888 M1Dep. on previous M2. Must be convinced thaterrors are due to slips not incorrect combination.11.9 (cm)A1www4(b)(Opp. angles of) cyclic quadrilateral(add to 180)B1Condone 180 70 110 o.e. (not spoilt)(c)70 – 37 attempted s.o.i.AD their(a)sin33 sin110(AD ) their (a) x sin33sin110art 6.89 or 6.90 (cm)M1M1e.g. 32 or 34 or 43, but be convinced.Dep. on first M1M1A1Dep. on M2Would imply M3 if nothing incorrect seen earlier.Condone 6.9 www4 Scale drawing gets M0A070B1If not 70, ft for method in (ii), but not from 90 or60(h )their(a)x tan55or their(a) (8.497.)22xtan35M1(EC or EA ) their(a)2 sin35(area ) 0.5 x their(a) x their(h)M1Dep. on first M1(area ) 0.5 x EC x EA x sin70 or Hero’s MethodA1www3Ignore all units in answers to Question 5.Not x 10/xQ4(a)(d)(i)(ii)o.e.o.e.50.4 to 50.8 (cm2)Q5(a)(b)10/x or 10 xo.e.B110xo.e.M210 1x 1220( x 1) 20x x( x 1)o.e.x2 x 20 0(c)(x 5)(x 4)(d)Rejects negative solution2.5 (hours)or their(a)2 cos55(10.37 )13Condone 30 for ½If M0 give Sc1 for10 s.o.i.x 1MA1 Dep on M2. No longer condoning 30 o.e.Sc1 for 20x – 20(x 1) x( x 1) o.e. after B1Sc1E1No error of any kind at any stage and sufficientworking to convince you (at least 1 extra step)M1c.a.o.A1 1 [12 4.1.( 20)] No errors or ambiguities2www2c.a.o.R1B1May be explicit or implicit and could be in (c)Condone 2 hrs 30 (mins) or 150 mins( 0) 5 and 4Scale drawing gets M0A0. University of Cambridge International Examinations 20049
Page 3Mark SchemeMATHEMATICS – JUNE 2004Q6(a)(i) 2 x π x 73 π x 72 x 13331384.7 to 1386 or 1380 or 1390 (cm3)Syllabus0580/0581Paper4M1A1www2their(a)(i) x 0.94M11.3 (kg)A2 ft their(a)(i) x 0.941000www3 If A2 not scored, allow A1 for 1.30 (b)(L ) (132 72)π x 7 x theirL324 to 326 (cm2)M1M1A1Implied by 218 or 14.7 . or 14.8Dep. on first M1.www3(c)CSA of hemisphere 2 x π x 72 s.o.i.their(b) their CSA631.7 to 634s.o.i.411.58their total( )0.649 to 0.652 or 64.9 to 65.2 centsM1M1A1M1307.7 to 308 if no workingDep. on first M1Seen or implied by subsequent working.Dep. on a totalA1www513NB M1M1A0M1A1 is not possible.-1 each error/omission. Condone lack of labels.(ii) Q7(a)(i) Venn Diagram with 12, 8, 7, 3or with 20 – x, x, 15 – x, 3(ii) 812(iii)30(iv)1220(b)(i) 3/9 x 4/1012 o.e.90(ii) 1 their(b)(i)78 o.e.90(iii)(iv)5/8 or 5/9 seen6/9 x 5/8 x 6/10 x 5/9 seen9006480 o.e.B2B1 ft their 8 on diagram, but not xo.e B2 ft (their 12)/30 from (i) or (ii)Sc1 for k/30 where k 30o.e. B2 ft (their 12)/20 from (i) or (ii) if their12 20Sc1 for m/20 where m 20In all of Q7, accept fractions, decimals or %.Mark as ISW for wrong cancelling. Dec. or %need to be exact or accurate to 3 sf. No ratios.Other inappropriate notation is 1 once.c.a.o.M1A1c.a.o.M1 or 6/9 x 6/10 6/9 x 4/10 3/9 x 6/10A1 ft 1 – their (b)(i)c.a.o.p(4 blacks) 3/9 x 2/8 x 4/10 x 3/9 ( 1/90)1 their(b)(iii) their p(4 blacks)55086480 o.e.c.a.o.M1M1A1M1M1A1Allow a slip in 1 digit, but must use 4 fractionsmultiplied.Simplest 5/36Alt. method. Must see all 14 combinations.Dep. on first M1.Must add themSimplest 17/20 University of Cambridge International Examinations 200417
Page 4Mark SchemeMATHEMATICS – JUNE 2004Q8(a)(i) Rotation (only)90 (anticlockwise)(about O) or ¼ turn(ii)(iii)(iv)Translation (only) 2 5 o.ePaper4B1B1“only” --- no other transformation mentioned.Ignore all matrices, except in (v).Do not allow “turn” for rotationAccept 270 clockwise or 270B1Not translocation,transformation,transportation.o.e. B1Reflection (only)y x.180 (or ½ turn) Rotation (only)Centre (1, 1)Syllabus0580/0581eg 2 to left and 5 down. Condone (–2 -5) andlack of brackets.B1B1B1B1Enlargement sf 1 earns B2Sc1 for “Point Symmetry”(v)Enlargement (only)Scale Factor 2 (centre O)B1B1Accept 2 0 for scale factor 20 2(vi)Shear (only)y axis invariant or parallel to y axisB1B1Ignore any mention of scale factor.BB2 1 0 0 1 B2Sc1 for a correct column 1 0 1 1 15x 25y 2000y xo.e.y 35o.e.B2Sc1 for a correct column(b)(c)(i)(ii)Q9 (a)(b)(c)(d)(i)(ii)18B1B2B1Allow 0.15x 0.25y 20 but no others.Sc1 for any other sign between x and yScales correct and full length.3x 5y 400 correct (1mm) at (0,80) and(100,20) and long enough.y x correcty 35 correctS1B2Reversed scales S0Sc1 for either point correct.Shading correct (in or out)B1 seenc.a.o.c.a.o.(e)38(f)Identifying any point(s) in their area(enclosed by 3 lines or 3 lines and 1 axis).(75 , 35) s.o.i.c.a.o.( ) 6.2(0) or 620 (cents)c.a.o.L1L1 ft from slips in lines that do notcompromise the idea of the triangle.B1M1A1B1 Implies M1 ft their (75, 35) evaluated for whole numbersonly.Condone lack of units but not wrong units.www314 University of Cambridge International Examinations 2004
MARK SCHEME for the June 2004 question papers 0580/0581 MATHEMATICS 0580/01, 0581/01 Paper 1 (Core), maximum raw mark 56 0580/02, 0581/02 Paper 2 (Extended), maximum raw mark 70 0580/03, 0581/03 Paper 3 (Core), maximum raw mark 104 0580/04, 0581/04 Paper 4 (Extended), maximum raw mark 130
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CSEC English A Specimen Papers and Mark Schemes: Paper 01 92 Mark Scheme 107 Paper 02 108 Mark Scheme 131 Paper 032 146 Mark Scheme 154 CSEC English B Specimen Papers and Mark Schemes: Paper 01 159 Mark Scheme 178 Paper 02 180 Mark Scheme 197 Paper 032 232 Mark Scheme 240 CSEC English A Subject Reports: January 2004 June 2004
Matthew 27 Matthew 28 Mark 1 Mark 2 Mark 3 Mark 4 Mark 5 Mark 6 Mark 7 Mark 8 Mark 9 Mark 10 Mark 11 Mark 12 Mark 13 Mark 14 Mark 15 Mark 16 Catch-up Day CORAMDEOBIBLE.CHURCH/TOGETHER PAGE 1 OF 1 MAY 16 . Proverbs 2—3 Psalms 13—15 Psalms 16—17 Psalm 18 Psalms 19—21 Psalms
Bruksanvisning för bilstereo . Bruksanvisning for bilstereo . Instrukcja obsługi samochodowego odtwarzacza stereo . Operating Instructions for Car Stereo . 610-104 . SV . Bruksanvisning i original
