Introduction To Fluid Mechanics

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Introduction to Fluid MechanicsGovind S KrishnaswamiChennai Mathematical Institutehttp://www.cmi.ac.in/ govindLectures at IISER Pune24-26 October, 2016

AcknowledgementsI am grateful to Sudarshan Ananth for the kind invitation to deliver theselectures at IISER Pune and to all of you for your interest andparticipation.The illustrations in these slides are scanned from books mentioned ordownloaded from the internet via Google images.Special thanks are due to PhD student Sonakshi Sachdev for her helpin preparing these slides.2/60

ReferencesFeynman R P, Leighton R and Sands M, The Feynman lectures on Physics: Vol 2,Addison-Wesley Publishing (1964). Reprinted by Narosa Publishing House (1986).Van Dyke M, An album of fluid motion, The Parabolic Press, Stanford, California (1988).Choudhuri A R, The physics of Fluids and Plasmas: An introduction for astrophysicists,Camb. Univ Press, Cambridge (1998).Tritton D J, Physical Fluid Dynamics, 2nd Edition, Oxford Science Publications (1988).Landau L D and Lifshitz E M , Fluid Mechanics, 2nd Ed. Pergamon Press (1987).Davidson P A, Turbulence: An introduction for scientists and engineers , Oxford UnivPress, New York (2004).Frisch U, Turbulence The Legacy of A. N. Kolmogorov Camb. Univ. Press (1995).3/60

Water, water, every where . . . (S T Coleridge, Rime of the Ancient Mariner)Whether we do physics, chemistry, biology, computation, mathematics,engineering or the humanities, we are likely to encounter fluids and befascinated and challenged by their flows.Fluid flows are all around us: the air through our nostrils, tea stirred in acup, eddies and turbulent flow in a river, plasmas in the ionosphere etc.From the standpoint of classical mechanics, a fluid is a continuumsystem with an essentially infinite number of degrees of freedom. Apoint particle has 3 translational degrees of freedom, a stone has threetranslational and 3 rotational degrees of freedom. On the other hand, tospecify the state of a fluid, we must specify the velocity at each point!We believe that the basic physical laws governing fluid motion are thoseof mass conservation, Newton’s laws and those of thermodynamics.The challenge lies in deducing the observed, often complex, patterns offlow from the known partial differential equations, boundary and initialconditions. This often requires a mix of physical insight, experimentaldata, mathematical techniques and computational methods.4/60

Water water every where . . .Some of the best scientists have worked on fluid mechanics: I Newton,D Bernoulli, L Euler, J L Lagrange, Lord Kelvin, H Helmholtz, C LNavier, G G Stokes, N Y Zhukovsky, M W Kutta, O Reynolds, L Prandtl,von Karman, G I Taylor, J Leray, L F Richardson, A N Kolmogorov, LOnsager, R P Feynman, L D Landau, S Chandrasekhar, OLadyzhenskaya, etc.Fluid dynamics finds application in numerous areas: flight of airplanesand birds, weather prediction, blood flow in the heart and blood vessels,waves on the beach, ocean currents and tsunamis, controlled nuclearfusion in a tokamak, jet engines in rockets, motion of charged particlesin the solar corona and astrophysical jets, formation of clouds, meltingof glaciers, global warming and sea level rise, traffic flow etc.Fluid flows can be regular (laminar) or chaotic (turbulent).Understanding turbulence is one of the great challenges of science.Fluid dynamics is among the 7 Clay Millenium Prize problems worth amillion dollars. The other physics problem is from particle physics.5/60

Continuum, Fluid element, Local thermal equilibriumIn fluid mechanics we are not interested in microscopic positions andvelocities of individual molecules. Focus instead on macroscopic fluidvariables like velocity, pressure, density, energy and temperature thatwe can assign to a fluid element by averaging over it.By a fluid element, we mean a sufficiently large collection of moleculesso that concepts such as ‘volume occupied’ make sense and yet smallby macroscopic standards so that the velocity, density, pressure etc. areroughly constant over its extent. E.g.: divide a container with 1023molecules into 10000 cells, each containing 1019 molecules.A flowing fluid is not in global thermal equilibrium. Collisions establishlocal thermodynamic equilibrium so that we can assign a localT, p, ρ, E, . . . to fluid elements, satisfying the laws of thermodynamics.Fluid description applies to phenomena on length-scale mean freepath. On shorter length-scales, fluid description breaks down, butkinetic theory of molecules (Boltzmann transport equation) applies.6/60

Eulerian and Lagrangian viewpointsIn the Eulerian description, we are interested in the time development offluid variables at a given point of observation r (x, y, z). Interesting ifwe want to know how density changes, say, above my head. However,different fluid particles will arrive at the point r as time elapses.It is also of interest to know how the corresponding fluid variablesevolve, not at a fixed location but for a fixed fluid element, as in aLagrangian description.This is especially important since Newton’s second law applies directlyto fluid particles, not to point of observation!So we ask how a variable changes along the flow, so that the observeris always attached to the same fluid element.7/60

Leonhard Euler and Joseph Louis LagrangeLeonhard Euler (left) and Joseph Louis Lagrange (right).8/60

Material derivative measures rate of change along flowChange in density of a fluid element in time dt as it moves from r tor dr isdρ ρ(r dr, t dt) ρ(r, t) ρdt dr · ρ. t(1)Divide by dt, let dt 0 and use v drdt to get instantaneous rate ofchange of density of a fluid element located at r at time t:Dρ ρ v · ρ.Dt t(2)Dρ/Dt measures rate of change of density of a fluid element as it movesaround. Material derivative of any quantity (scalar or vector) s in a flowfield v is defined as DsDt t s v · s.Material derivative of velocity DvDt t v v · v gives the instantaneousacceleration of a fluid element with velocity v located at r at time t.As a 1st order differential operator it satisfies Leibnitz’ product ruleD(fg)DgDf f gDtDtDtand9/60D(ρv)DvDρ ρ v .DtDtDt(3)

Continuity equation and incompressibilityRate of increase of mass in a fixed vol V is equal to the influx of mass.Now, ρv · n̂ dS is the mass of fluid leaving a volume V through a surfaceelement dS per unit time. Here n̂ is the outward pointing normal. Thus,ddtZρdr VZ Vρv · n̂ dS ZZ · (ρv) dr ρt · (ρv) dr 0. VVAs V is arbitrary, we get continuity equation for local mass conservation: t ρ · (ρv) 0In terms of material derivative, t ρ v · ρ ρ · v 0.orDρDt(4) ρ · v 0.DρFlow is incompressible if Dt 0: density of a fluid element is constant.Since mass of a fluid element is constant, incompressible flowpreserves volume of fluid element.Alternatively imcompressible means · v 0, i.e., v is divergence-freeor solenoidal. · v limV,δt 0 δt1 δVV measures fractional rate of change ofvolume of a small fluid element.Most important incompressible flow is constant ρ in space and time.10/60

Sound speed, Mach numberIncompressibility is a property of the flow and not just the fluid! Forinstance, air can support both compressible and incompressible flows.Flow may be approximated as incompressible in regionsq where flowspeed is small compared to local sound speed cs adiabatic flow of an ideal gas with γ cp /cv .Compressibility β ρ p p ρ pγp/ρ formeasures increase in density with pressure.Incompressible fluid has β 0, so c2 1/β . An approximatelyincompressible flow is one with very large sound speed (cs v ).Common flows in water are incompressible. So study of incompressibleflow is called hydrodynamics. High speed flows in air/gases tend to becompressible. Compressible flow is called aerodynamics/ gas dynamics.Incompressible hydrodynamics may be derived from compressible gasdynamic equations in the limit of small Mach number M v /cs 1.At high Mach numbers M 1 we have super-sonic flow andphenomena like shocks.11/60

Newton’s 2nd law for fluid element: Inviscid Euler equationConsider a fluid element of volume δV . Mass acceleration is ρ(δV) DvDt .Force on fluid element includes ‘body force’ like gravity derived from apotential φ. E.g. F ρ(δV) φ where φ is acceleration due to gravity.Also have surface force on a volume element, due to pressure exertedon it by neighbouring elementsFsurface Newton’sZp n̂ dS Vnd2 lawZ pdV;if V δVthen Fsurf p(δV).Vthen gives the celebrated (inviscid) Euler equation v p v · v φ; tρv · v ‘advection term’(5)Continuity & Euler eqns. are first order in time derivatives: to solve initialvalue problem, must specify ρ(r, t 0) and v(r, t 0).Boundary conditions: Euler equation is 1st order in space derivatives;impose BC on v, not i v. On solid boundaries normal component ofvelocity vanishes v · n̂ 0. As r , typically v 0 and ρ ρ0 .12/60

Isaac NewtonIsaac Newton13/60

Barotropic flow and specific enthalpyEuler & continuity are 4 eqns for 5 unknowns ρ, v, p. Need another eqn.In local thermodynamic equilibrium, pressure may be expressed as afunction of density and entropy. For isentropic flow it reduces to abarotropic relation p p(ρ). It eliminates p and closes the system ofequations. E.g. p ργ adiabatic flow of ideal gas; p ρ for isothermal.In barotropic flow, p/ρ can be written as the gradient of an ‘enthalpy’h(ρ) ZFor example, h ρρ0p0 (ρ̃)p0 (ρ) pdρ̃ h h0 (ρ) ρ ρ .ρ̃ρργ pγ 1 ρ(6)for adiabatic flow of an ideal gas.Reason for the name enthalpy: 1st law of thermodynamicsdU TdS pdV becomes dH TdS Vdp for enthalpy H U pV . Foran isentropic process dS 0, so dH Vdp.Dividing by mass of fluid M we get d(H/M) (V/M)dp. Definingenthalpy per unit mass h H/M and density ρ M/V gives dh dp/ρ.14/60

Barotropic flow and conserved energyIn barotropic flow p p(ρ) and p/ρ is gradient of enthalpy h. So theEuler equation becomes t v v · v h.(7)Using the vector identity v · v ( 12 v2 ) ( v) v, we get1 t v ( v) v h v22!where1 h p.ρ(8)Barotropic flow has a conserved energy: kinetic compressionalE Z "#1 2ρv U(ρ) d3 r,2whereU 0 (ρ) h(ρ).(9)γ pFor adiabatic flow of ideal gas, h γ 1 ρ and U p/(γ 1). In the caseof a monatomic ideal gas γ 5/3 and compressional energy takes thefamiliar form (3/2)pV (3/2)NkT .More generally, the Euler and continuity equations are supplemented byan equation of state and energy equation (1st law of thermodynamics).15/60

Flow visualization: Stream-, Streak- and Path-linesIf v(r, t) v(r) is time-independent everywhere, the flow is steady.Stream, streak and pathlines coincide forsteady flow. They are the integral curves(field lines) of v, everywhere tangent to v:drdx dy dz v(r(s)) or ;dsvx vy vzr(so ) ro .In unsteady flow, streamlines at time t0 encode the instantaneousvelocity pattern. Streamlines at a given time do not intersect.Path-lines are trajectories of individualfluid ‘particles’ (e.g. speck of dust stuckto fluid). At a point P on a path-line, it istangent to v(P) at the time the particlepassed through P. Pathlines can(self)intersect at t1 , t2 .16/60

Streak-linesStreak-line: Dye is continuously injected into aflow at a fixed point P. Dye particle sticks to thefirst fluid particle it encounters and flows with it.Resulting high-lighted curve is the streak-linethrough P. So at a given time of observation tobs ,a streak-line is the locus of all current locationsof particles that passed through P at some timet tobs in the past.17/60

Steady Bernoulli principleEuler’s equation for barotropic flow subject to a conservative body forcepotential Φ (e.g. Φ gz for gravity at height z) is v1 ( v) v B where B v2 h Φ t2(10)For steady flow t v 0. Dotting with v we find the Bernoulli specificenergy B is constant along streamlines: v · B 0.For incompressible (constant density) flow, enthalpy h p/ρ. Thus alonga streamline 12 v2 p/ρ gz is constant. For roughly horizontal flow,pressure is lower where velocity is higher.E.g. Pressure drops as flowspeeds up at constrictions ina pipe. Try to separate twosheets of paper by blowingair between them!18/60

Daniel BernoulliDaniel Bernoulli19/60

Vorticity and circulationVorticity w v is a measure of localrotation/angular momentum in a flow. A flowwithout vorticity is called irrotational.Eddies and vortices are manifestations ofvorticity in a flow. [w] 1/T , a frequecy.Given a closed contour C in a fluid, theHcirculation around the contour Γ(C) C v · dlmeasures how much v ‘goes round’ C. ByStokes’ theorem, it equals the flux of vorticityacross a surface that spans C.Γ(C) Iv·dl CZ( v)·dS SZw·dS where S C.SREnstrophy w2 dr measures global vorticity. It is conserved in ideal 2dflows, but not in 3d: it can grow due to ‘vortex stretching’ (see below).20/60

Examples of flow with vorticity w vShear flow with horizontal streamlines is anexample of flow with vorticity:v(x, y, z) (U(y), 0, 0). Vorticityw v U 0 (y)ẑ.A bucket of fluid rigidly rotating at small angularvelocity Ωẑ has v(r, θ, z) Ωẑ r Ωrθ̂. Thecorresponding vorticity w v 1r r (rvθ )ẑ isconstant over the bucket, w 2Ωẑ.The planar azimuthal velocity profile v(r, θ) cr θ̂has circular streamlines. It has no vorticityw 1r r (r cr )ẑ 0 except at r 0: w 2πcδ2 (r)ẑ.The constant 2πc comes from requiring the fluxof w to equal the circulation of v around anycontour enclosing the originIv · dl I(c/r)r dθ 2πc.21/60

Evolution of vorticity and Kelvin’s theorem Taking the curl of the Euler equation t v ( v) v h 12 v2allows us to eliminate the pressure term in barotropic flow to get t w (w v) 0.(11)This may be interpreted as saying that vorticity is ‘frozen’ into v.The flux of w through a surface moving with the flow is constant in time:ZIddΓdw · dS 0 or by Stokes’ theoremv · dl 0.(12)dt Stdt CtdtHere Ct is a closed material contour moving with the flow and St is asurface moving with the flow that spans Ct .The proof uses the Leibnitz rule for material derivatives Dt t v · IIIdv · dl Dt v · dl v · Dt dl.(13)dt CtCtCtUsing the Euler equation Dt v h and Dt dl dv we get!IId1v · dl d v2 h 0.dt Ct2Ct22/60(14)

Kelvin & Helmholtz theorems on vorticity 0 is Kelvin’s theorem: circulation around a material contouris constant in time. In particular, in the absence of viscosity, eddies andvortices cannot develop in an initially irrotational flow (i.e. w 0 at t 0).Vortex tubes are cylindrical surfaces everywheretangent to w. So on a vortex tube, w · dS 0.Hddt Ct v · dlThe circulation Γ around a vortex tube is independentof the choice of encircling contour. Consider part of avortex tube S between two encircling contours C1 andC2 spanned by surfaces S1 and S2 .Applying Stokes’ theorem to the closed surface Q S1 S S2 we getZZQZ w · dS S1w · dS Z Qv · dl 0 as Q is empty,w · dS 0 or Γ(C1 ) Γ(C2 ) since w · dS 0 on S.S2As a result, a vortex tube cannot abruptly end, it must close on itself toform a ring (e.g. a smoke ring) or end on a boundary.23/60

Helmholtz’s theorem: inviscid flow preserves vortex tubesSuppose we have a vortex tube at initial timet0 . Let the material on the tube be carried byflow till time t1 . We must show that the newtube is a vortex tube, i.e., that vorticity iseverywhere tangent to it, or w · dS 0.Consider a contractible closed curve C(t0 ) lying on the initial vortextube, the flow maps it to a contractible closed curve C(t1 ) lying on thenew tube. By Kelvin’s theorem, Γ(C(t0 )) 0 Γ(C(t1 )). Now suppose Sis the surface on the new vortex tube enclosed by C(t1 ), S C(t1 ), then0 Γ(C(t1 )) Zw · dS.SThis is true for any contractible closed curve C(t1 ) on the new tube.Considering an infinitesimal closed curve, we conclude that w · dS 0 atevery point of the new tube, i.e., it must be a vortex tube.24/60

Vortex rings and vortex stretchingSmoke rings are examples of vortex tubes. Dolphins blow vortex rings inwater and chase them.Kelvin’s theorem implies that the strength Γ of a vortex tube isindependent of time.Fluid flow tends to stretch and bend vortex tubes.Since Γ w · dS is independent of time for a vortex tube, if the crosssection of a vortex tube decreases, the vorticity must increase.RThis typically leads to growth of enstrophy25/60Rw2 dr.

Lord Kelvin and Hermann von HelmholtzLord Kelvin (left) and Hermann von Helmholtz (right).26/60

Irrotational incompressible inviscid flow around cylinderWhen flow is irrotational (w v 0) we may writev φ. Velocity potential φ is like the electrostaticpotential in E φ which guarantees E 0.Incompressibility · v 0 φ satisfies Laplace’s equation 2 φ 0.We impose impenetrable boundary conditions: normal component of φvelocity vanishes on solid surfaces: n̂ 0 on boundary (Neumann BC).For flow with asymptotic velocity U x̂ past a fixed cylinder of radius a,translation invariance along z-axis makes this a 2d problem in r, θ plane. φThe BCs are r 0 at r a and φ Ur cos θ as r (so v Ux̂).Separating variables, gen. soln. to 2 φ (1/r) r (r r φ) (1/r2 ) 2θ φ 0 isφ (A0 B0 ln r) XAn rn n 1Bn (Cn cos nθ Dn sin nθ).rn(15)Imposing BC at we get A0 B0 An Cn Dn 0 except for A12 Uand C1 1. The BC at r a gives B1 Ua2 . Thus φ U cos θ r ar .2The corresponding velocity field is v φ Ux̂ U ar2 (cos θ r̂ sin θ θ̂).27/60

Potential flow and the added mass effectVelocity field for potential flow (v φ) past a2cylinder is v Ux̂ U ar2 (cos θ r̂ sin θ θ̂).Now consider problem of a cylinder moving withvelocity Ux̂ through a fluid asymptotically at rest.By a Galilean transformation, the velocity field around the cylinder is2v0 v U x̂ U ra02 (cos θ0 r̂0 sin θ0 θ̂0 ) where r0 , θ0 are relative to thecenter of the cylinder.This example can be used to illustrate the added mass effect. The forcerequired to accelerate a body (of mass M at U̇ ) through potential flowexceeds M U̇ , since part of the force applied goes to accelerate the fluid.! !2 4Indeed the flow KE 12 ρ a (v0 )2 r0 dr0 dθ0 21 ρ Ur03a dr0 dθ0 21 ρπa2 U 2 12 M 0 U 2 is quadratic in U just like the KE of cylinder itself. Thus thetotal KE of cylinder fluid is Ktotal 12 (M M 0 )U 2 .The associated power to be supplied is K̇total F · U . So a forceF (M M 0 )U̇ is required to accelerate the body at U̇ . Body behaves asif it has an effective mass M M 0 . M 0 is its added or virtual mass. Shipsmust carry more fuel than expected after accounting for viscosity.28/60

Sound waves in compressible flowSound waves are excitations of the ρ or p fields. Arise in compressibleflows, where regions of compression and rarefaction can form.Notice first that a fluid at rest (v 0) with constant pressure and density(p p0 , ρ ρ0 ) is a static solution to the continuity and Euler equations t ρ · (ρv) 0 and ρ( t v v · v) p.(16)Now suppose the stationary fluid suffers a small disturbance resulting insmall variations δv, δp and δρ in velocity, pressure and densityv 0 v1 (r, t),ρ ρ0 ρ1 (r, t) and p p0 p1 (r, t).(17)What can the perturbations v1 (r, t), p1 (r, t) and ρ1 (r, t) be? They must besuch that v, p and ρ satisfy the continuity and Euler equations withv1 , p1 , ρ1 treated to linear order (as they are assumed small).It is found empirically that the small pressure and density variations areproportional i.e., p1 c2 ρ1 . We will derive the simplest equation forsound waves by linearizing the continuity and Euler eqns around thestatic solution. It will be possible to interpret c as the speed of sound.29/60

Sound waves in static fluid with constant p0 , ρ0Ignoring products of sma

Choudhuri A R, The physics of Fluids and Plasmas: An introduction for astrophysicists, Camb. Univ Press, Cambridge (1998). Tritton D J, Physical Fluid Dynamics, 2nd Edition, Oxford Science Publications (1988). Landau L D and Lifshitz E M ,

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