10th Bangladesh Mathematical Olympiad: Selected Problems .

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10thBangladesh Mathematical Olympiad:Selected Problems and SolutionsEditor: Masum BillalSpecial Thanks:Nur Muhammad ShafiullahMd Sanzeed AnwarAsif-E-ElahiNayeemul Islam Swad

PrologueThis booklet contains selected problems used in the training and selection process of the IMO team that participated in IMO 2015. Many of the problems aretaken from IMO Shortlisted problems. And many other are taken from otherolympiads. We are grateful to the problem setters of those problems. Theyhelped a lot in our training process. We hope it wouldn’t raise any legal issuerelated to copyrights for using those problems since they were by no means usedfor any commercial gain. So we apologize in advance if it’s any inconveniencefor anyone. Also, thanks to anyone who contributed to the training process inany way, including our MOVERs(Math Olympiad Volunteers), who took careof the participants in the camp.I am very grateful to Mahi, Sanzeed, Asif and Swad for their time andcontribution. At first, I wanted to create this document all by myself. Butlater I realized I don’t have enough time for that. So, I invited Mahi. Later onI had to invite others too because we both got busy. Whereas it should havebeen published in 2015, I couldn’t do it until now. Therefore, it goes withoutsaying that they had a lot to do with it.Another point I should mention is that, all problems may not have solutionright now or some might contain typos. Probably in a later version, we willupdate it. If there are any typos or errors in solutions or any suggestions, feelfree to email me: billalmasum93@gmail.comMasum BillalUniversity Of DhakaDepartment of Computer Science and EngineeringDhakaBangladeshi

You can use this document in any form as long as you don’tbenefit commercially. Moreover, one of my primary motivations to create this document was to encourage othercountries to publish their booklets as well. Because manycountries tend to keep their training problems and materials secret. Therefore, you can share it as much as you want,and also enable others to share their booklet too.

Bangladesh Mathematical OlympiadIn Bangladesh, students face at least twelve stages of primary, secondary andhigher secondary education. Excluding pre-school studies, one has to study inclasses 1 12. Grades 1 to 5 are considered primary, 6 10 secondary and11 12 is higher secondary. Mathematical competitions in Bangladesh aredivided into four categories:1. Primary Students of class 1 5.2. Junior Students of class 6 8.3. Secondary Students of class 9 10.4. Higher Secondary Students of class 11 12.It is to be noted that, we treat the participants of secondary and higher secondary category almost equally. Therefore, most problems posed for these twocategories are about same.Two contests are held: one on a regional level and the other on a nationallevel. At first, regional contests are held in different districts, 21 this year.In a district, a school provides the venue of the regional olympiad. Participants who are awarded gets to participate in the national olympiad. Theolympiads take place in a festive manner and the national level olympiad isknown as BdMO(Bangladesh Mathematical Olympiad). Around 40 participants are chosen as campers of the national math camp, where some exams areheld in order to determine the team for the IMO. Sometimes, there is an extension camp, where around 20 campers are called for in order to take part in mockexams of Team Selection Tests. Finally a pool of at most six students isselected to represent Bangladesh at the International Mathematical Olympiad.ii

IMO Contestants of 2015From right to left in figure (1), the members are: Asif E Elahi2015 Bronze, 2014 HM Nayeemul Islam Swad2015 HM Adib Hasan2015, 14, 13 Bronze, 2012 HM Sazid Akhter Turzo2015 Bronze, 2014 HM Sanzeed Anwar2015 Silver, 2014 HM Sabbir Rahman Abir2015 Bronzeiii

Figure 1: Bangladesh IMO Team 2015, at the IMO Campiv

Trainer Panel of 2015This year the following trainers contributed in the math camps by taking classesand setting problemsets.1. Dr. Mahbub Majumdar (coach of BdMO and leader of our IMO team)2. Masum Billal3. Nur Muhammad ShafiullahSpecial thanks to Muhammad Milon(A BIG THANK YOU to him. He cheeredup and entertained everyone throughout his classes when all the campers werein the ICU called national math camp) and Zadid Hasan.v

Contents1 National Olympiad Problems1.1 Primary Category . . . . . .1.2 Junior Category . . . . . . .1.3 Secondary Category . . . . .1.4 Higher Secondary Category .2 National Math Camp2.1 Geometry . . . . .2.2 Number Theory . .2.3 Combinatorics . . .2.4 Mock Exam 1 . . .2.5 Mock Exam 2 . . .3 Extension Camp3.1 Exam One . . .3.2 Geometry . . .3.3 Number Theory3.4 Combinatorics .3.5 Mock Exam 1 .3.6 Mock Exam 2 .vi.11479.131317202426.28283438404345

Notations a divides b is denoted by a b (a, b) gcd(a, b) is the greatest common divisor of a and b. [a, b] lcm(a, b) is the least common multiple of a and b. τ (a) is the number of divisors of a. σ(n) is the sum of divisors of n. ϕ(n) is the number of positive integers less than or equal to n which areco-prime to n. π(n) is the number of primes less than or equal to n. νp (n) α is the largest positive integer so that pα n but pα 6 n. Λ(n) is the Van Mangoldt Function.vii

Chapter 1National Olympiad Problems1.1.Primary CategoryProblem 1.1.1. Write down all the prime numbers in the range of 1 to 50.Solution. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47Problem 1.1.2. Four people A, B, C and D have an average monthly income of 10000 taka.First three of them have an average monthly income of 12000 taka. Average income of firsttwo of them is 15000 taka. Find the monthly income of B, C and D if A has a monthlyincome of 20000 taka.Solution. Let a, b, c, d denote their respective incomes. Then the given conditions are:(1.1.1)(1.1.2)(1.1.3)(1.1.4)a b c d 10000 a b c d 400004a b c 12000 a b c 360003a b 15000 a b 300002a 20000(3) and (4) b 10000(2) and (3) c 6000(1) and (2) d 4000Problem 1.1.3. In the following figures a rectangular piece of paper ABCD has beenfolded several times. First, the side CD was made to fall on the line AD. Point E in1

figure (ii) represents the point C after folding. In the next figure the portion BF wasmade to fall on EF . Lastly, the side AG was made to fall on GH. Find the lengths ofGJ, IJ, IE, ED, EH and HF . It is given that AB 8 and BC 15.Solution.Solution ED EF AB 8HF BF AE AD ED BC ED 15 8 7EH EF HF AB HF 8 7 1GJ GA EH 1IJ EH 1IE AE AI BF AI HF AI HF GJ 7 1 6Problem 1.1.4. A circus party has the same number of lions as tigers. You asked to theowner of the circus the number of lions and tigers. He gave you the following information:i. An elephant is enough to feed all the tigers and lions in the circus.ii. Eighteen deers produce the same amount of meat as an elephant does.iii. A lion eats twice as much as a tiger.iv. One buffalo is enough to feed a lion and a tiger.v. A tiger will eat exactly the same amount of meat a deer has.Find the number of tigers and lions in that circus party.Solution. Let the number of tigers(and lions)be x.1. All of 2x animals eat in total 3x(a single tiger’s food).2. 3x(a single tiger’s food) an elephant.3. 3x(a single tiger’s food) 18 deer.2

4. 3x(a single tiger’s food) 18(a single tiger’s food)So, 3x 18 x 6.Problem 1.1.5. Surjo is four years old and he is learning to write numbers. His mathnotebook looks like a square grid with 20 rows and 20 columns. He usually writes thenumbers from top to bottom and when one column is finished he starts writing along thenext column. One day he starts writing the numbers from left to right (along the rows).How many of the numbers will be placed in exactly the same place where it would haveappeared if he had written along the columns?Solution. Let n be such a number which remained in the position in both of the writingmethods.Let x and y be the row and column number of n, respectively, 1 x, y 20.Then following the order of the numbers in the vertical writing method,n 20(y 1) xAgain by the horizontal writing method,n 20(x 1) y 20(y 1) x n 20(x 1) y x ySo, x must be equal to y and there are 20 such pairs. So they correspond to 20 possiblevalues for n.Problem 1.1.6. In the following figure BKLGN M, CM N HP O and DOP IRQ are regularhexagons (all six sides of each hexagon are equal and so are the angles). BKLGN M has anarea of 24 square units. What is the area of the rectangle AF JE?3

Solution. Let the center of the hexagon BKLGN M be O andOB OG AF a. Then2area[BKLGN M ] 6 area[OBK] 4 area[OBK] 246 23a 4 44 a 438 AF 43Again, 4OKL equilateral and with side-length a, so, altitude So, F J 6 altitude of 4OKL 12 4 3 area[AF JE] AF F J 961.2. 3a2 243Junior CategoryProblem 1.2.1. A small country has a very simple language. People there have only twoletters and all their words have exactly seven letters. Calculate the maximum number ofwords people can use in that country.Solution. There are two possibilities for each letter. So 27 possibilities for the 7 letters. Sothey can use at most 27 words.Problem 1.2.2. In the following figures, the larger circles are identical and so are the smallerones. In (i) the circles have a common center and the lines AD and BC divide both thecircles in four equal halves. The larger circle has an area of 100 square meters. Find thearea of the shaded region in figure(ii).4

Solution. area[circleABCD] 100 area[XDC] 25rarea[ABCD] p 100/π 2 radius of small circleradius of ABCD π 25So, area[small circle] π 25ππarea[small circle] area of the shaded region area[XDC] 225 25 π2Problem 1.2.3. A circus party has the same number of lions as tigers. You asked to theowner of the circus the number of lions and tigers. He gave you the following information:i. An elephant is enough to feed all the tigers and lions in the circus.ii. Eighteen deers produce the same amount of meat as an elephant does.iii. A lion eats twice as much as a tiger.iv. One buffalo is enough to feed a lion and a tiger.v. A tiger will eat exactly the same amount of meat a deer has.Find the number of tigers and lions in that circus party.Solution. Let the number of tigers(and lions)be x.1. All of 2x animals eat in total 3x(a single tiger’s food).2. 3x(a single tiger’s food) an elephant.3. 3x(a single tiger’s food) 18 deer.4. 3x(a single tiger’s food) 18(a single tiger’s food)So, 3x 18 x 6.Problem 1.2.4. In the following figure BKLGN M, CM N HP O and DOP IRQ are regularhexagons (all six sides of each hexagon are equal and so are the angles). BKLGN M has anarea of 24 square units. What is the area of the rectangle AF JE?Solution. Let the center of the hexagon BKLGN M be O andAF a. ThenOB OG 2area[BKLGN M ] 6 area[OBK]5

24 4 area[OBK] 6 23a 444 a 438 AF 43 Again, 4OKL equilateral and with side-length a, so, altitude So, F J 6 altitude of 4OKL 12 4 3 area[AF JE] AF F J 96 3a 2432Problem 1.2.5. In a party, boys shake hands with girls only but each girl shakes handswith everyone else. If there are total 40 handshakes, find the number (more than one) ofboys and girls in the party.Solution. Let the number of boys in the party be x and the number of girls be y. Theneach boy shakes hands exactly y times and each girl shakes hands y (x 1) times. So thetotal number of handshakes will be xy y(y x 1) y(2x y 1) y(2x y 1) 40Now a little checking for y over the factors of 40 shows us that only for y 5(y 1) we geta positive integral value for x( 8).Problem 1.2.6. ABCD is a parallelogram, where ACB 80 , ACD 20 . P is apoint on AC such that, ABP 20 and Q is a point on AB such that ACQ 30 . Findthe magnitude of the angle determined by the lines CD and P Q.Solution. Let P Q meet CD at K and the parallel from P to BC meet AB at F . Let CFmeet BP at G. Since 4BCG is equilateral, BG BC. Since 4CBQ is isosceles BQ BC.Hence 4BGQ is isosceles, BGQ 80 , F GQ 40 6

Since QF G 40 , 4F QG is isosceles and F Q QG. Also P F P G. Hence 4GP Q 4F P Q, P Q bisects F P G, and QP B 30 . Now CKQ CP Q KCP ( CP B BP Q) KCP (40 30 ) 20 50 .1.3.Secondary CategoryProblem 1.3.1. A crime is committed during the hortal. There are four witnesses. Thewitnesses are logicians and make the following statements. Witness one says exactly one of the witnesses are liar Witness one says exactly two of the witnesses are liar Witness one says exactly three of the witnesses are liar Witness one says exactly four of the witnesses are liarAssume that each of the statements are true or false. Find the number of liar witnesses.Solution. All the 4 witnesses provided 4 different kind of informations and any two of themcannot be true at the same time. So there can be at most 1 truthful. Again all 4 of themcannot be liar otherwise the 4th person will be truthful. So there are exactly 3 liars.7

Problem 1.3.2. There were 36 participants in a BdMO event. Some of the participantsshook hand with each other. No two of them shook hands with each more than once. Itwas found that no two participants with the same number of handshakes made, had shakenhands each other. Find the maximum number of handshakes at the party.Solution. Suppose that the number of participants who shook hands with exactly i otherparticipants is f (i). Then, due to the given

In a district, a school provides the venue of the regional olympiad. Partic-ipants who are awarded gets to participate in the national olympiad. The olympiads take place in a festive manner and the national level olympiad is known as BdMO(Bangladesh Mathematical Olympiad). Around 40 partici-

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