Chapter 1: Chemical Bonding - LSU

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Chapter 1: Chemical BondingLinus Pauling (1901–1994)January 30, 2017Contents1 The development of Bands and their filling32 Different Types of Bonds72.1Covalent Bonding . . . . . . . . . . . . . . . . . . . . . . . . . . . . .82.2Ionic Bonding . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .122.2.1Madelung Sums . . . . . . . . . . . . . . . . . . . . . . . . . .142.3Metallic Bonding . . . . . . . . . . . . . . . . . . . . . . . . . . . . .152.4Van der Waals Bonds . . . . . . . . . . . . . . . . . . . . . . . . . . .152.4.117Van der Waals-London Interaction . . . . . . . . . . . . . . .1

Figure 1: Periodic Chart2

Solid state physics is the study of mainly periodic systems (or things that areclose to periodic) in the thermodynamic limit 1021 atoms/cm3 . At first this wouldappear to be a hopeless task, to solve such a large system.Figure 2: The simplest model of a solid is a periodic array of valance orbitals embeddedin a matrix of atomic cores.However, the self-similar, translationally invariant nature of the periodic solid andthe fact that the core electrons are very tightly bound at each site (so we may ignoretheir dynamics) makes approximate solutions possible. Thus, the simplest model ofa solid is a periodic array of valance orbitals embedded in a matrix of atomic cores.Solving the problem in one of the irreducible elements of the periodic solid (cf. oneof the spheres in Fig. 2), is often equivalent to solving the whole system. For thisreason we must study the periodicity and the mechanism (chemical bonding) whichbinds the lattice into a periodic structure. The latter is the emphasis of this chapter.1The development of Bands and their fillingWe will imagine that each atom (cf. one of the spheres in Fig. 2) is composed ofHydrogenic orbitals which we describe by a screened Coulomb potentialV (r) Znl e2r3(1)

nlelemental solid1sH,He2sLi,Be2p B Ne3sNa,Mg3p Al Ar4sK,Ca3d transition metals Sc Zn4p Ga Kr5sRb,Sr4d transition metals Y Cd5p In-Xe6sCs,Ba4fRare Earths (Lanthanides) Ce Lu5d Transition metals La Hg6p Tl RnTable 1: Orbital filling scheme for the first few atomic orbitalswhere Znl describes the effective charge seen by each electron (in principle, it willthen be a function of n and l). As electrons are added to the solid, they then fillup the one-electron states 1s 2s 3s 3p 3d 4s 4p 4d 4f· · · , where the correspondencebetween spdf and l is s l 0, p l 1, etc. The elemental solids are thenmade up by filling these orbitals systematically (as shown in Table 1) starting withthe lowest energy states (where Enl 2me4 Znl2 22h̄ nNote that for large n, the orbitals do not fill up simply as a function of n as wewould expect from a simple Hydrogenic model with En mZ 2 e42h̄2 n2(with all electronsseeing the same nuclear charge Z). For example, the 5s orbitals fill before the 4d!This is because the situation is complicated by atomic screening. I.e. s-electrons cansample the core and so are not very well screened whereas d and f states face the4

4spdfCe Valence Shell3spd2sp 6s4f5ds1sV(r) C l (l 1)/r2Figure 3: Level crossings due to atomic screening. The potential felt by states withlarge l are screened since they cannot access the nucleus. Thus, orbitals of differentprinciple quantum numbers can be close in energy. I.e., in elemental Ce, (4f 1 5d1 6s2 )both the 5d and 4f orbitals may be considered to be in the valence shell, and formmetallic bands. However, the 5d orbitals are much larger and of higher symmetry thanthe 4f ones. Thus, electrons tend to hybridize (move on or off ) with the 5d orbitalsmore effectively. The Coulomb repulsion between electrons on the same 4f orbital willbe strong, so these electrons on these orbitals tend to form magnetic moments.angular momentum barrier which keeps them away from the atomic core so thatthey feel a potential that is screened by the electrons of smaller n and l. To put isanother way, the effective Z5s is larger than Z4d . A schematic atomic level structure,accounting for screening, is shown in Fig. 3.Now let’s consider the process of constructing a periodic solid. The simplest modelof a solid is a periodic array of valence orbitals embedded in a matrix of atomic cores(Fig. 2). As a simple model of how the eigenstates of the individual atoms are modifiedwhen brought together to form a solid, consider a pair of isolated orbitals. If they arefar apart, each orbital has a Hamiltonian H0 n, where n is the orbital occupancyand we have ignored the effects of electronic correlations (which would contribute5

terms proportional to n n ). If we bring them together so that they can exchangeFigure 4: Two isolated orbitals. If they are far apart, each has a Hamiltonian H0 n,where n is the orbital occupancy.electrons, i.e. hybridize, then the degeneracy of the two orbitals is lifted. Suppose theFigure 5: Two orbitals close enough to gain energy by hybridization. The hybridizationlifts the degeneracy of the orbitals, creating bonding and antibonding states.system can gain an amount of energy t by moving the electrons from site to site (Ourconclusions will not depend upon the sign of t. We will see that t is proportional tothe overlap of the atomic orbitals). ThenH (n1 n2 ) t(c†1 c2 c†2 c1 ) .(2)where c1 (c†1 ) destroys (creates) an electron on orbital 1. If we rewrite this in matrixform H c†1 , c†2 t t c1c2 (3)then it is apparent that system has eigenenergies t. Thus the two states split theirdegeneracy, the splitting is proportional to t , and they remain centered at If we continue this process of bringing in more isolated orbitals into the regionwhere they can hybridize with the others, then a band of states is formed, again with6

. . . BandEFigure 6: If we bring many orbitals into proximity so that they may exchange electrons(hybridize), then a band is formed centered around the location of the isolated orbital,and with width proportional to the strength of the hybridization.width proportional to t, and centered around (cf. Fig. 6). This, of course, is anoversimplification. Real solids are composed of elements with multiple orbitals thatproduce multiple bonds. Now imagine what happens if we have several orbitals oneach site (ie s,p, etc.), as we reduce the separation between the orbitals and increasetheir overlap, these bonds increase in width and may eventually overlap, formingbands.The valance orbitals, which generally have a greater spatial extent, will overlapmore so their bands will broaden more. Of course, eventually we will stop gainingenergy (t̃) from bringing the atoms closer together, due to overlap of the cores. Oncewe have reached the optimal point we fill the states 2 particles per, until we run outof electrons. Electronic correlations complicate this simple picture of band formationsince they tend to try to keep the orbitals from being multiply occupied.2Different Types of BondsThese complications aside, the overlap of the orbitals is bonding. The type of bondingis determined to a large degree by the amount of overlap. Three different generalcategories of bonds form in solids (cf. Table 2).7

BondOverlapLatticeconstituentsIonicvery small ( a)closest unfrustrateddissimilarpackingCovalentsmall ( a)determined by thesimilarstructure of the orbitalsMetallicvery large ( a) closest packedunfilled valenceorbitalsTable 2: The type of bond that forms between two orbitals is dictated largely by theamount that these orbitals overlap relative to their separation a.2.1Covalent BondingCovalent bonding is distinguished as being orientationally sensitive. It is also shortranged so that the interaction between nearest neighbors is of prime importance andthat between more distant neighbors is often neglected. It is therefore possible todescribe many of its properties using the chemistry of the constituent molecules.Consider a simple diatomic molecule O2 with a single electron andH 2Ze2 Ze2 Z 2 e2 2mrarbR(4)We will search for a variational solution to the the problem of the molecule (HΨmol EΨmol ), by constructing a variational wavefunction from the atomic orbitals ψa andψb . Consider the variational molecular wavefunctionΨ0 ca ψa cb ψbR 0 Ψ HΨ00RE EΨ0 Ψ0The best Ψ0 is that which minimizes E 0 . We now define the quantum integralsZZZ S ψa ψb Haa Hbb ψa Hψa Hab ψa Hψb .8(5)(6)(7)

Note that 1 Sr 0, and that Habr 0 since ψa and ψb are bound states [whereSr ReS and Habr ReHab ]b. With these definitions,(c2a c2b )Haa 2ca cb Habrc2a c2b 2ca cb SrE0 and we search for an extremum E 0 ca E 0 cb(8)0 0. From the first condition, E 0 and caafter some simplification, and re-substitution of E 0 into the above equation, we getthe conditionca (Haa E 0 ) cb (Habr E 0 Sr ) 0The second condition, E 0 cb(9) 0, givesca (Habr E 0 S) cb (Haa E 0 ) 0 .(10)Together, these form a set of secular equations, with eigenvaluesE0 Haa Habr.1 Sr(11)Remember, Habr 0, so the lowest energy state is the state. If we substituteEq. 10 into Eqs. 8 and 9, we find that the state corresponds to the eigenvector ca cb 1/ 2; i.e. it is the bonding state.1Haa Habr0Ψ0bonding (ψa ψb ) Ebonding.(12) 1 Sr2 For the , or antibonding state, ca cb 1/ 2. Thus, in the bonding state, thewavefunctions add between the atoms, which corresponds to a build-up of charge between the oxygen molecules (cf. Fig. 7). In the antibonding state, there is a deficiencyof charge between the molecules.Energetically the bonding state is lower and if there are two electrons, both willoccupy the lower state (ie., the molecule gains energy by bonding in a singlet spinconfiguration!). Energy is lost if there are more electrons which must fill the antibonding states. Thus the covalent bond is only effective with partially occupiedsingle-atomic orbitals. If the orbitals are full, then the energy loss of occupying the9

erarbRZespin tripletspin singletZeΨanti-bondingΨbondingFigure 7: Two oxygen ions, each with charge Ze, bind and electron with charge e.The electron, which is bound in the oxygen valence orbitals will form a covalent bondbetween the oxygensantibonding states would counteract the gain of the occupying the bonding state andno bond (conventional) would occur. Of course, in reality it is much worse than thissince electronic correlation energies would also increase.The pile-up of charge which is inherent to the covalent bond is important for thelattice symmetry. The reason is that the covalent bond is sensitive to the orientationof the orbitals. For example, as shown in Fig. 8 an S and a Pσ orbital can bond if bothare in the same plane; whereas an S and a Pπ orbital cannot. I.e., covalent bonds aredirectional! An excellent example of this is diamond (C) in which the (tetragonal)lattice structure is dictated by bond symmetry. However at first sight one mightassume that C with a 1s2 2s2 2p2 configuration could form only 2-bonds with the twoelectrons in the partially filled p-shell. However, significant energy is gained frombonding, and 2s and 2p are close in energy (cf. Fig. 3) so that sufficient energy isgained from the bond to promote one of the 2s electrons. A linear combination of the10

-PσPπSS - No bondingBondingFigure 8: A bond between an S and a P orbital can only happen if the P-orbital isoriented with either its plus or minus lobe closer to the S-orbital. I.e., covalent bondsare directional!2s 2px , 2py and 2pz orbitals form a sp3 hybridized state, and C often forms structures(diamond) with tetragonal symmetry.Another example occurs most often in transition metals where the d-orbitals tryto form covalent bonds (the larger s-orbitals usually form metallic bonds as describedlater in this chapter). For example, consider a set of d-orbitals in a metal with aface-centered cubic (fcc) structure, as shown in Fig. 9. The xy, xz, and yz orbitals allface towards a neighboring site, and can thus form bonds with these sites; however,the x2 y 2 and 3z 2 r2 orbitals do not point towards neighboring sites and thereforedo not participate in bonding. If the metal had a simple cubic structure, the situationwould be reversed and the x2 y 2 and 3z 2 r2 orbitals, but not the xy, xz, and yzorbitals, would participate much in the bonding. Since energy is gained from bonding,this energetically favors an fcc lattice in the transition metals (although this may notbe the dominant factor determining lattice structure).One can also form covalent bonds from dissimilar atoms, but these will also havesome ionic character, since the bonding electron will no longer be shared equally bythe bonding atoms.11

zzdxzzydxyxxzdx2- y2yydyzyxFace CenteredCubic Structurezd2 23z - rxyxFigure 9: In the fcc structure, the xy, xz, and yz orbitals all face towards a neighboringsite, and can thus form bonds with these sites; however, the x2 y 2 and 3z 2 r2 orbitalsdo not point towards neighboring sites and therefore do not participate in bonding2.2Ionic BondingThe ionic bond occurs by charge transfer between dissimilar atoms which initiallyhave open electronic shells and closed shells afterwards. Bonding then occurs byCoulombic attraction between the ions. The energy of this attraction is called thecohesive energy. This, when added to the ionization energies yields the energy releasedwhen the solid is formed from separated neutral atoms (cf. Fig. 10). The cohesiveenergy is determined roughly by the ionic radii of the elements. For example, forNaClEcohesive e2ao 5.19eV .ao rN a rCl(13)Note that this does not agree with the experimental figure given in the caption ofFig. 10. This is due to uncertainties in the definitions of the ionic radii, and tooversimplification of the model. However, such calculations are often sufficient todetermine the energy of the ionic structure (see below). Clearly, ionic solids are12

insulators since such a large amount of energy 10eV is required for an electron tomove freely.NaFigure 10: 5.14 eVCl Na Na e-Cl- 3.61 eVNa Cl-Cl-e-r Cl 1.81r Na 0.97 7.9 eVThe energy per molecule of a crystal of sodium chloride is (7.9-5.1 3.6) eV 6.4eV lower than the energy of the separated neutral atoms. The cohesive energy with respect to separated ions is 7.9eV per molecular unit. All values onthe figure are experimental. This figure is from Kittel.The crystal structure in ionic crystals is determined by balancing the needs ofkeeping the unlike charges close while keeping like charges apart. For systems with like ionic radii (i.e. CsCl, rCs 1.60 A, rCl 1.81 A) this means the crystal structurewill be the closest unfrustrated packing. Since the face-centered cubic (fcc) structureis frustrated (like charges would be nearest neighbors), this means a body-centeredcubic (bcc) structure is favored for systems with like ionic radii (see Fig. 11). Forsystems with dissimilar radii like NaCl (cf. Fig. 10), a simple cubic structure is favored.13

This is because the larger Cl atoms requires more room. If the cores approach closerthan their ionic radii, then since they are filled cores, a covalent bond including bothbonding and anti-bonding states would form. As discussed before, Coulomb repulsionmakes this energetically unfavorable.Body CenteredCubicCubicFace CenteredCubicClcClbbaNacaCsFigure 11: Possible salt lattice structures. In the simple cubic and bcc lattices all thenearest neighbors are of a different species than the element on the site. These ioniclattices are unfrustrated. However, it not possible to make an unfrustrated fcc latticeusing like amounts of each element.2.2.1Madelung SumsThis repulsive contribution to the total energy requires a fully-quantum calculation.However, the attractive Coulombic contribution may be easily calculated, and therepulsive potential modeled by a power-law. Thus, the potential between any twosites i and j, is approximated byφij Be2 nrij rij(14)where the first term describes the Coulombic interaction and the plus (minus) sign isfor the potential between similar (dissimilar) elements. The second term heuristicallydescribes the repulsion due to the overlap of the electronic clouds, and contains twofree parameters n and B (Kittel, pp. 66–71, approximates this heuristic term with14

an exponential, B exp ( rij /ρ), also with two free parameters). These are usuallydetermined from fits to experiment. If a is the separation of nearest neighbors, rij apij , and their are N sites in the system, then the total potential energy may bewritten as#B X 1e2 X .(15)Φ N Φi N a i6 j pij an i6 j pnijPThe quantity A i6 j p ij , is known as the Madelung constant. A depends upon the"type of lattice only (not its size). For example AN aCl 1.748, and ACsCl 1.763.Due to the short range of the potential 1/pn , the second term may be approximatedby its nearest neighbor sum.2.3Metallic BondingMetallic bonding is characterized by at least some long ranged and non-directionalbonds (typically between s orbitals), closest packed lattice structures and partiallyfilled valence bands. From the first characteristic, we expect some of the valanceorbitals to encompass many other lattice sites, as discussed in Fig. 12. Thus, metallicbonds lack the directional sensitivity of the covalent bonds and form non-directionalbonds and closest packed lattice structures determined by an optimal filling of space.In addition, since the bands are composed of partially filled orbitals, it is possibleto supply a small external electric field and move the valence electrons through thelattice. Thus, metallic bonding leads to a relatively high electronic conductivity. Inthe transition metals (Ca, Sr, Ba) the d-band is narrow, but the s and p bonds areextensive and result in conduction. Partially filled bands can occur by bond overlaptoo; ie., in Be and Mg since here the full S bonds overlap with the empty p-bands.2.4Van der Waals BondsAs a final subject involving bonds, consider solids formed of Noble gases or composedof molecules with saturated orbitals. Here, of course, there is neither an ionic norcovalent bonding possibility. Furthermore, if the charge distributions on the atoms15

3d x2 - y24SFigure 12: In metallic Ni (fcc, 3d8 4s2 ), the 4s and 3d bands (orbitals) are almostdegenerate (cf. Fig. 3) and thus, both participate in the bonding. However, the 4sorbitals are so large compared to the 3d orbitals that they encompass many otherlattice sites, forming non-directional bonds. In addition, they hybridize weakly withthe d-orbitals (the different symmetries of the orbitals causes their overlap to almostcancel) which in turn hybridize weakly with each other. Thus, whereas the s orbitalsform a broad metallic band, the d orbitals form a narrow one.were rigid, then the interaction between atoms would be zero, because the electrostaticpotential of a spherical distribution of electronic charge is canceled outside a neutralatom by the electrostatic potential of the charge on the nucleus. Bonding can resultfrom small quantum fluctuations in the charge which induce electric dipole moments.As shown in Fig. 13 we can model the constituents as either induced dipoles, ormore correctly, dipoles formed of harmonic oscillators. Suppose a quantum fluctuationon 1 induces a dipole moment p1 . Then dipole 1 exerts a fieldE1 3n(p1 · n) p1r3(16)which is felt by 2, which in turn induces a dipole moment p2 E1 1/r3 . This inturn, generates a dipole field E2 felt by 1 p2 /r3 1/r6 . Thus, the energy of the16

nP1P2x1 -R x2Figure 13: Noble gasses and molecules with saturated orbitals can form short rangedvan der Waals bonds by inducing fluctuating electric dipole moments in each other.This may be modeled by two harmonic oscillators binding a positive and negativecharge each.interaction is very small and short ranged.W p1 · E2 1/r62.4.1(17)Van der Waals-London InteractionOf course, a more proper treatment of

2; i.e. it is the bonding state. 0 bonding 1 p 2 (a b) E0 bonding H aa H abr 1 S r: (12) For the , or antibonding state, c a c b 1 p 2. Thus, in the bonding state, the wavefunctions add between the atoms, which corresponds to a build-up of charge be-tween the oxygen molecules (cf

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