Chapter 4:Solving LiteralEquations1
Day 1: The Basics of Literal EquationsA-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.Warm-UpWhat is a literal equation?A literal equation is an equation with two or more variables. Instead of solving for a numerical value, we solvefor one variable in terms of another. A formula is one type of literal equation that has special applications inmath or science.Observe the similarities between the linear equation (left) and the literal equation (right):One-Step Linear Equation:1) y 10 553)s 40 85 solve for sTwo-Step Linear Equation:5) 2a 13 87 solve for aOne-Step Literal Equation:2)y x 55 solve for y4)s x 85 solve for sTwo-Step Literal Equation:6)2a b c solve for a2
Solving for a variable using division:7)3x 458)3x y solve for xQuick Check for Understanding9)2 x y 9 solve for y10) 3b c d solve for b11)P mvsolve for mApplication12) The formula d rt relates the distance an object travels, d, to its average rate of speed r, and amount oftime t that it travels.a) Solve the formulad rtfor t.b) How many hours would it take for a car to travel 150 miles at an average rate of 50 miles per hour?3
Independent PracticeSolve for the variable indicated.1) π ππ‘ ππππ£π πππ π2) π π π ππππ£π πππ π3) π¦ ππ₯ π ππππ£π πππ π₯4) π π π ππππ£π πππ π5) π΄π₯ π΅ πΆ ππππ£π πππ π₯6) π΄π₯ π΅π¦ πΆ ππππ£π πππ π¦7) πΌ πππ‘ ππππ£ππππ π8) πΆ ππ ππππ£π πππ π4
9) π ππ ππππ£π πππ π10) πΈ πΌπ ππππ£π πππ π 11) πΈ ππ 2 ππππ£π πππ π 212) π 13) 5π π 10 ππππ£π πππ π14) 5 π 2π‘ ππππ£π πππ π‘15) ππ ππ π ππππ£ππππ π 16) π¦ 2π 2π€ππππ£π πππ π¦3π₯ 1 ππππ£π πππ π₯5
17) The volume of a prism is π ππ€β.a) Solve this formula for β.b) If the volume of a prism is 64, its length 4, and its width 2, what is its height?SummaryHomeworkChapter 4- Day 1 -Textbook pp. 109-110 #2, 5, 8, 9, 10, 11, 14, 20, 23, 26, 36-376
Day 2: Solving Literal Equations with ProportionsA-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.Warm-UpModel ProblemsSolving ProportionsSolve for x in each equation.Linear Equations:π₯1) 933) 2π₯ 1 32Literal Equation:π₯2) π¦34)π₯2 π 67
25) 10 (x 4)36) D 115(π₯ 15)Reminder: Donβt distribute acoefficient unless absolutely necessary!Application57) The formula to convert Celsius to Fahrenheit is given by C (πΉ 32) .9a) Solve this formula for F.b) The boiling point of water is 100 . What is the Fahrenheit equivalent of this temperature?8
8) Check for Understandinga)π ππSolve for the given variable.b)solve for nπ΄ π π2c)π πππ£π πππ ππΉ πΊπ1 π2π2solve for π11d) The formula for the mean (average) π΄ of two numbers y and z is one-half their sum, or π΄ (π¦ π§).2If the average of two numbers is 7 and one of the numbers is 4, find the other number.Cumulative Independent Practice1)ππ π₯ πππ πDays 1-2Solve for the value of the variable.12) π π΄β πππ π΄39
13) π ππ‘ 2 πππ π25) π π 7)π₯7π5πππ π π¦ π‘ πππ π₯4) π π€ 10ππ6) π π 8)π₯ π¦7π5πππ π€πππ π π‘ πππ π₯10
9)π₯ π¦7 π‘ πππ π¦11)π πΆ π13)π π¦2 π¦1π‘πππ πΆπ₯2 π₯1πππ π¦210)π π πΆ πππ πΆ12)2π₯ 7π¦ 14 πππ π¦14)π (π₯ 2π¦) for x23115) The formula π ππ 2β is the formula for the volume of a cylinder. To the nearest tenth, what is the height3of a cylinder with volume 100 cm3 and radius 2 cm?HW Chapter 4-Day 2 Textbook pp. 109-110 #6, 7, 12, 13, 15, 18, 24, 30, 4511
Day 3: Using the Distributive Property and Rational EquationsA-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.Warm-UpThe formula π 2(πΏ π) is the formula for the perimeter of a rectangle. Solve this formula for L.What is the length of a rectangle whose perimeter is 48 and whose width is 6?Distribution and Reverse distribution1) When there is a common factor in all terms of an expression, we can use the distributive property in reverseto write it in factored form.Simplest forma)2πΏ 2πFactored Form2(πΏ π)b) 3π 3πc)2ππ€ 2πd) ππ ππe) 2ππβ 2ππ 22) Model ProblemUsing the Distributive Property in ReverseSolve for c in terms of a and b: ππ ππ ππ12
3) Practicea)b)Using Rational Equations4) Model Problem11 1relates an objectβs distance, π, and its imageβs distance, π, to the focal length of theπππlens, π. Solve this formula for π.The formula5) PracticeThe total resistance in a circuit is given by the formula1π 1π 1 1. Solve this formula for π 1.π 213
Unit Summary So Far:Look for STRUCTURE in equations:One- or Two-Step EquationsProportionsπ΄π₯ π΅ πΆπ₯ π πReverse Distribution (Common Factor)π· ππΎ π1) π ππ for n3) π 2π₯ π‘ππππ π₯2ππ£ 2π₯Μ π₯1 π₯22Rational Equations (Sums and Differences)111 πΆ πΆ1 πΆ2S 2ππ 2 2ππβCumulative Practice/Homework Chapter 4 β Day 31Solve for the requested variable.2) π 13π΅β πππ π΅4) π£ π£0 ππ‘ for π£014
5) π½ ππ£π ππ£π for m6) πΈ πΌπ πππ πΌ7) π¦ π¦1 π(π₯ π₯1 )πππ π₯8) π ππβ πππ π9) π πππ΄πππ π΄10) πΉ π πΈ 2 πππ π15
11) π 12ππ πππ π13) πΊ π» ππ πππ π»15) π π0 ππβ for h12) π§ π¦ π₯ π₯π¦ 2 πππ π₯14) πΉπΆ 16) π ππ£ 2πππ» ππΆππ»for mπππ ππ»16
Multiple Choice Practice.17)18)Real-World Application.19)If Patty paid 0.93 to mail her letter, how manyounces was it? (C cost, z ounces)17
Day 4: Square RootsA-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.Warm-UpMini-Lesson: Using Square RootsTo solve for a squared variable, take its square root.Linear Equation:64 16π₯ 2Check for UnderstandingLiteral Equation:π΄ ππ 2 solve for rSolve for the indicated variable.11) The formula for kinetic energy is πΎ ππ£ 2.2Write an expression for π£ in terms of K and π.2) The gravitational force F that two planetary bodiesexert on one another is given by πΉ Solve this formula for π.πΊπ1 π2π2.18
Cumulative Practice/Homework1)π ππ€βSolve for h3) A 1 h(b1 b2 )Solve for h25) Solve π Solve for the value of the indicated variable.π 3π€2for w12) π ππ‘ 2 solve for t24) ππππ£π πππ π:π π3 π 56) Solve ππ₯ ππ¦ π 0 πππ π¦19
7) π΄ 2ππβ 2ππ 2 Solve for Ο8) Rewrite πΎ 9) π 3π 210) In π ππ₯ π , what is a in terms of x and b?11)5 π6ππππ£π πππ π π 7 Solve for c12) ππ π£2π32ππ solved for T in terms of k and T.Solve for π£20
Regents Practice.13)14)15)16)21
Day 5: ReviewA-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters.Look for STRUCTURE in equations:One-Step Equations1) πΌ πππ‘ Solve for π.2) π π π Solve for M.Two-Step Equations3) 5π‘ 2π 25 Solve for t.4) π£π‘ 16π‘ 2 Solve for v.Proportions5) πΉ ππ‘7) π΄ 1π2Solve for l.β(π π) Solve for a.6) π 8) π 144ππ¦Solve for p.π¦2 π¦1π₯2 π₯1Solve for π¦222
Reverse Distribution9) π π ππ Solve for R.10) ππ₯ ππ₯ πSolve for x.Rational Equations11)1πΆ 1πΆ1 1πΆ2π₯π₯34Solve for πΆ112) Solve for v.14) π πSolve for x.Square Roots13) πΎ 12ππ£ 213ππ 2β Solve for r.Applications. The surface area of a sphere is given by the formula π 4ππ 2. Solve this formula for r. Whatis the radius of a sphere whose surface area is 201 ππ2?23
A-REI.3 Solve linear equations and inequalities in one variable, including equations with coefficients represented by letters. Look for STRUCTURE in equations: One-Step Equations 1) Solve for . 2) Solve for M. Two-Step Equations 3) 5 2 25
9.1 Properties of Radicals 9.2 Solving Quadratic Equations by Graphing 9.3 Solving Quadratic Equations Using Square Roots 9.4 Solving Quadratic Equations by Completing the Square 9.5 Solving Quadratic Equations Using the Quadratic Formula 9.6 Solving Nonlinear Systems of Equations 9 Solving Quadratic Equations
literal and non-literal language. Some, such as Bach (1999), remain undaunted by these concerns and steadfastly maintain the need for a literalβnon-literal distinction. Others, however, have argued eloquently against a coherent notion of literal meaning, and suggest the futility of eve
2-literal Watching In a L-literal clause, L 3, which 2 literals should we watch? 48 Comparison: NaΓ―ve 2-counters/clause vs 2-literal watching When a literal is set to 1, update counters for all clauses it appears in Same when literal is set to 0 If a literal i
Lesson 2a. Solving Quadratic Equations by Extracting Square Roots Lesson 2b. Solving Quadratic Equations by Factoring Lesson 2c. Solving Quadratic Equations by Completing the Square Lesson 2d. Solving Quadratic Equations by Using the Quadratic Formula What I Know This part will assess your prior knowledge of solving quadratic equations
CONCEPT IN SOLVING TRIG EQUATIONS. To solve a trig equation, transform it into one or many basic trig equations. Solving trig equations finally results in solving 4 types of basic trig equations, or similar. SOLVING BASIC TRIG EQUATIONS. There are 4 types of common basic trig equations: sin x a cos x a (a is a given number) tan x a cot x a
Part One: Heir of Ash Chapter 1 Chapter 2 Chapter 3 Chapter 4 Chapter 5 Chapter 6 Chapter 7 Chapter 8 Chapter 9 Chapter 10 Chapter 11 Chapter 12 Chapter 13 Chapter 14 Chapter 15 Chapter 16 Chapter 17 Chapter 18 Chapter 19 Chapter 20 Chapter 21 Chapter 22 Chapter 23 Chapter 24 Chapter 25 Chapter 26 Chapter 27 Chapter 28 Chapter 29 Chapter 30 .
5.7 Literal Equations Now that we have learned to solve a variety of different equations (linear equations in chapter 2, polynomial equations in chapter 4, and rational equations in the last section) we want to take a look at solving another type of equation which will draw upo
EQUATIONS AND INEQUALITIES Golden Rule of Equations: "What you do to one side, you do to the other side too" Linear Equations Quadratic Equations Simultaneous Linear Equations Word Problems Literal Equations Linear Inequalities 1 LINEAR EQUATIONS E.g. Solve the following equations: (a) (b) 2s 3 11 4 2 8 2 11 3 s