1MA1 Practice Tests Set 1: Paper 3F (Regular) Mark Scheme .

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0QuestionAnswerMark118 0001B1 cao21B1 cao31910000.351B1 cao4drawn1B1 for isosceles triangle drawn5 or 7462 or 54B1 5 or 7B1 caoB1 caoB1 2 or 519 152M1 for 17 55 1 20 (oe) or a complete build up method or1875 or 1835A1 for 19 15 , 7 15 p.m. (or equivalent)391B1 ft 19:54 – ‘19 15’5(i)(ii)(iii)(iv)6(i)(ii)Working17 55 1 20or17:55 5min 18:0018:00 1 hr 19:0019:00 15 min 19:1518 34 – 17 551MA1 practice paper 3F (Set 1) mark scheme: Version 1.01Notes

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question7(a)(b)(c)Working20 20 402.2 40AnswerMark253.588113B1 25 or 25.0B1 3.5 caoM1 20 20 ( 40)M1 2.2 ‘40’A1 caoORM1 2.2 20 ( 44)M1 ‘44’ ‘44’A1 cao132M1 for 40A1 caoOR2.2 20 4444 4489Notes(a)40(b)9–3 4 6 4 243M1 for subtraction of 3 or times 4M1 (dep) for subtraction of 3 and times 4A1 caoNB: the above could be shown as part of an equation.26 3 8 2 38remainder 28 90 238 796 7.96 or 796p5M1 for attempting to add carton prices or 26 3M1 26 38 or 988 seen4 3 10 3 1MA1 practice paper 3F (Set 1) mark scheme: Version 1.04 3M1 for “8” 90 “2” 38A1 7.96 or 796pC1 ft (dep on M1) “ 7.96” is the least they can spend2

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question10Working0.1 240( 24)216 ‘24’1112AnswerMark9 weeks4M1 for 0.1 240 (oe), e.g. 240 10A1 for 24M1 for 216 ‘24’A1 for 92M1 for conversion to decimals or conversion to percentages orcorrect order with one error or correct order but largest firstA1for correct orderB1B1 for 4x or 4xB1 for – 3ySC: Award B1 for: 4x – 3y followed by an incorrect expressionM1 for 6x 16 5 or 6x 21 or (16 5) 6 or 6x – 21 0or – 6x – 21 0; Condone omission of brackets or 16.8(333.)721A1 for 3.5 or oroe26132070%0.6 0.6223(a)(i)(ii)3d²4x – 3y12(b)3.521MA1 practice paper 3F (Set 1) mark scheme: Version 1.03Notes

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0QuestionWorking*13AnswerMarkYes there is enoughwater in bucket C4NotesM12 3 5 3 4 6M189 10oe with at least one correct numerator 12 12 12A127oe12C1 (dep on M1) yes,27oe 2, there is enough water in the12bucket 12 27OR23M1 1 – 1 –3443M1oe with at least one correct numerator 12 127A1oe125 10 7C1 (dep on M1) yes, , there is enough water in the 6 12 12bucketNB Accept decimals if written correct or truncated to 2 d.p.1MA1 practice paper 3F (Set 1) mark scheme: Version 1.04

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question1415Working78 119 105 302360 – 302 58180–58(a)15 6*(b)1MA1 practice paper 3F (Set 1) mark scheme: Version 1.0AnswerMarkNotes3M1 360 – (78 119 105) or 360 – 302 or 58 seenM1 (indep) 180 – “58” where the “58” must be 90 and not78 from the diagram.A1 cao2.52M1 for 15 6 oe1A1 for 2.5 or 22Yes evidence2M1 for a correct method to change 15 miles into kilometresC1(dep on M1) for 24 km and statement with correctconclusion[SC: B1 for “Yes” oe and 24 km shown if M0 scored]ORM1 for a correct method to change 20 kilometres into milesC1(dep on M1) for 12.5 miles and statement with correctconclusion[SC: B1 for “Yes” oe and 12.5 miles shown if M0 scored]1225

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question*16WorkingAngle BAC 76 Angle BAP 180 – 90 – 54 36 x 76 – 36 Answer40oMarkNotes4B1 for Angle BAC 76 (could be just on the diagram)M1 for 76 – (“180 – 90 – 54 ”)A1 for x 40 (explicitly stated)C1 (dep on M1) for ‘the sum of the angles of a triangle is 180 ’and ‘alternate angles on parallel lines are equal’ORB1 for Angle QCD 54 (could be just on the diagram)M1 for 180 – 90 – (“180 – 76 – 54 ”)A1 for x 40o (explicitly stated)C1 (dep on M1) for ‘corresponding angles on parallel lines areequal’ and ‘sum of the angles on a straight line is 180o’ and‘the sum of the angles of a triangle is 180o’or ‘corresponding angles on parallel lines are equal’ and‘exterior angle of a triangle is equal to the sum of the twointerior opposite angles’ORM1 for angle QCB 180 – 54 ( 126)M1 for 180 – 90 – “126 – 76”A1 for x 40o (explicitly stated)ORAngle QCD 54 Angle ACP 180 – 76 – 54 50 x 180 90 – 50 C1 (dep on M1) for ‘sum of allied angles 180 ’ and ‘the sumof the angles of a triangle is 1801MA1 practice paper 3F (Set 1) mark scheme: Version 1.06

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question17AnswerMark(a)3, – 6, – 52B2 cao for all 3 (B1 for any 1 or 2 correct)(b)Quadratic graph20.3, 3.72B2 for a fully correct graphORB1 for all 7 points ft on (a) plotted correctly 1 sqB1 for a smooth curve through all 7 of their plotted pointsdepending on at least B1 in (a)B1 for 0.2 – 0.4 or ft from graph 1 squareB1 for 3.6 – 3.8 or ft from graph 1square(SC: If no marks earned then B1 for line y – 3 drawn)(c)18WorkingDraw y 348.45 100425Katie spends more3NotesM1 for48.45 100425A1 for 11.4C1 (dep on M1)for conclusion ft from comparison of twopercentagesOROR11 425 or for 10% 42.5(0), 1% 4.25,10042.5(0) 4.25A1 for 46.75C1 (dep on M1) for correct follow-through from comparison of“46.75” and 48.45M1 for11 425 46.751001MA1 practice paper 3F (Set 1) mark scheme: Version 1.07

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0Question19Working1 10 2 5 22 212.5πAnswer39.3Mark5NotesM1 for π 5 ( 78.5(39 )) or π 102 ( 314(.159 )) or100π or 25π2M1 for1 10 2 ( 157(.07 )) or 50π2M1 (dep on at least one of the previous Ms) for1 10 2 – 5 221M1 (dep on previous M) for ( 10 2 – 5 2 ) 2 or2'157.07.' '78.53.'or 25π/22A1 for answer in range 39.2 – 39.3ORM1 for π 52 ( 78.5(39 )) or π 102 ( 314(.159 )) or100π or 25πM1 for1 10 2 ( 78.5(398 )) or 25π4M1 for1 5 2 ( 39.2(69 )) or 12.5π2M1(dep on 2 previous Ms) for ’78.5’ – ’39.2’A1 for answer in range 39.2 – 39.31MA1 practice paper 3F (Set 1) mark scheme: Version 1.08

1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 2(a)51415436, green37.22(b)(c)221MA1 practice paper 3F (Set 1) mark scheme: Version 1.09NotesB1 caoM1: [(4 0)] (5 1) (10 2) (7 3) (3 4) (1 5)Or [0] 5 20 21 12 5(condone one error or omission or for 67 given as total)A1 caoM1 for an attempt to divide the number of customers by thenumber of tablesA1 for 2.1 or ft from (a) and (b)B1 for5oe fraction14M1 for 84 (5 9) ( 6) or 1 – “(a)” ( )M1 for 84 (5 9) 9 oe orA1 caoM1 for correct method to find twice as many green beads as redbeads, e.g. 2 30 ( 60) or 2 (84 – “54”) or “54” “6” ( 60)A1 for 6 (green) OR if n reds are added then 2n 6 (greens),where n and 2n could be numbers OR 30 (red) and 60 (green)C1 (dep on M1) for showing correct relevant working and clearconclusion stating number of green beads or stating totalnumbers of red beads and green beadsx8.5A1 for answer in range 7.2 to 7.21M1 starts process, e.g. cos 32

National performance data from Results PlusSource of questionsQu12345678910111213141516171819202122Mean score of students achieving 7Q12NEW1MA1 practice paper 3F (Set 1) mark scheme: Version 1.0TopicRoundingDecimals and fractionsProbabilityConstructionsFactors; multiples, primesTime calculationsConversionsSubstitution into expressionsFour operationsPercentagesFractions, percentages, decimalsSimplify expressionsRatioInterior and exterior anglesCompound measuresAnglesGraphs of quadratic equationsPercentagesArea of a circleGrouped 5425434463557280Mean% .371.872.471.272.072.744.96DENo data availableNo data availableNo data availableNo data 50.231.160.410.430.000.600.332.001.522.530.95No data .100.111.161.01

1MA1 practice paper 3F (Set 1) mark scheme: Version 1.0 4 1MA1 Practice Tests Set 1: Paper 3F (Regular) mark scheme – Version 1.0 Question Working Answer Mark Notes *13 Yes there is enough water in bucket C 4 M1 6 5 4 3 3 2 M1 12 10 12 9 12 8 oe with at least on