4-3: The Remainder And Factor Theorems

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4-3The Remainder andFactor TheoremsonRSKIING On December 13,1998, Olympic championp li c a tiHermann (The Herminator) Maierwon the super-G at Val d’Isere, France. Hisaverage speed was 73 meters per second.The average recreational skier skis at aspeed of about 5 meters per second.Suppose you were skiing at a speed of5 meters per second and heading downhill,accelerating at a rate of 0.8 meter per secondsquared. How far will you travel in 30 seconds?This problem will be solved in Example 1.Ap Find the factorsof polynomialsusing theRemainderand FactorTheorems.l WorealdOBJECTIVEHermann MaierConsider the polynomial function f(a) 2a2 3a 8. Since 2 is a factor of 8,it may be possible that a 2 is a factor of 2a2 3a 8. Suppose you use longdivision to divide the polynomial by a 2.2a 7divisora 2 a 2 a3 8 2quotientdividend2a2 4a7a 87a 146remainderFrom arithmetic, you may remember that the dividend equals the product of thedivisor and the quotient plus the remainder. For example, 44 7 6 R2, so44 7(6) 2. This relationship can be applied to polynomials.You may wantto verify that(a 2)(2a 7) 6 2a2 3a 8.RemainderTheoremf(a) (a 2)(2a 7) 6Let a 2. f(2) (2 2)[2(2) 7] 6 0 6 or 6 f(a) 2a2 3a 8f(2) 2(22 ) 3(2) 8 8 6 8 or 6Notice that the value of f(2) is the same as the remainder when the polynomialis divided by a 2. This example illustrates the Remainder Theorem.If a polynomial P(x) is divided by x r, the remainder is a constant P(r), andP(x) (x r)Q(x) P(r),where Q(x) is a polynomial with degree one less than the degree of P(x).The Remainder Theorem provides another way to find the value of thepolynomial function P(x) for a given value of r. The value will be the remainderwhen P(x) is divided by x r.222Chapter 4Polynomial and Rational Functions

l WoreaAponldRExamplep li c a ti1 SKIING Refer to the application at the beginning of the lesson. The formula1for distance traveled is d(t) v0t at 2, where d(t) is the distance2traveled, v0 is the initial velocity, t is the time, and a is the acceleration.Find the distance traveled after 30 seconds.1The distance formula becomes d(t) 5t (0.8)t 2 or d(t) 0.4t 2 5t. You2can use one of two methods to find the distance after 30 seconds.Method 1Divide 0.4t 2 5t by t 30.Method 2Evaluate d(t) for t 30.0.4t 0172t 30 0.4 t 50 t 00 0 0.4t 2 12t17t 017t 510510 D(30) 510d(t) 0.4t 2 5td(30) 0.4(302 ) 5(30) 0.4(900) 5(30) 510By either method, the result is the same. You will travel 510 meters in30 seconds.Long division can be very time consuming. Synthetic division is a shortcutfor dividing a polynomial by a binomial of the form x r. The steps for dividingx3 4x2 3x 5 by x 3 using synthetic division are shown below.Step 1 Arrange the terms of the polynomial inx3 4x2 3x 5descending powers of x. Insert zerosfor any missing powers of x. Then,14 3 5write the coefficients as shown.For x 3, thevalue of r is 3.Step 2Write the constant r of the divisorx r. In this case, write 3. 314 3 5Step 3Bring down the first coefficient. 3114 3 5Step 4Multiply the first coefficient by r. Thenwrite the product under the nextcoefficient. Add. 31 3 5 14 31Multiply the sum by r. Then write theproduct under the next coefficient.Add. 31 14 31 3 5 3 6Repeat Step 5 for all coefficients in thedividend. 314 31 3 5 3 18 6 13Step 5Notice that avertical barseparates thequotient from theremainder.Step 6 Step 71The final sum represents the remainder, which in this case is 13. Theother numbers are the coefficients of the quotient polynomial, which hasa degree one less than the dividend. Write the quotient x2 x 6 withremainder 13. Check the results using long division.Lesson 4-3The Remainder and Factor Theorems223

Example2 Divide x3 x2 2 by x 1 using synthetic division. 11 1 11 202 Notice there is no x term. A zero is placed in this2 2 position as a placeholder.20The quotient is x2 2x 2 with a remainder of 0.In Example 2, the remainder is 0. Therefore, x 1 is a factor of x3 x2 2.If f(x) x3 x2 2, then f( 1) ( 1)3 ( 1)2 2 or 0. This illustrates theFactor Theorem, which is a special case of the Remainder Theorem.FactorTheoremExampleThe binomial x r is a factor of the polynomial P(x) if and only ifP(r) 0.3 Use the Remainder Theorem to find the remainder when 2x3 3x2 x isdivided by x 1. State whether the binomial is a factor of the polynomial.Explain.Find f(1) to see if x 1 is a factor.f(x) 2x3 3x2 xf(1) 2(13) 3(12 ) 1 2(1) 3(1) 1 or 0Replace x with 1.Since f(1) 0, the remainder is 0. So the binomial (x 1) is a factor of thepolynomial by the Factor Theorem.When a polynomial is divided by one of its binomial factors x r, thequotient is called a depressed polynomial. A depressed polynomial has a degreeless than the original polynomial. In Example 3, x 1 is a factor of 2x3 3x2 x.Use synthetic division to find the depressed polynomial.122 312 1 100002x 2 1x 0Thus, (2x 3 3x2 x)(x 1) 2x2 x.The depressed polynomial is 2x2 x.A depressed polynomial may also be the product of two polynomial factors,which would give you other zeros of the polynomial function. In this case, 2x2 xequals x(2x 1). So, the zeros of the polynomial function f(x) 2x 3 3x2 x1are 0, , and 1.2224Chapter 4Polynomial and Rational Functions

Note that thevalues of r whereno remainderoccurs are alsofactors of theconstant term ofthe polynomial.You can also find factors of apolynomial such as x3 2x2 16x 32 byusing a shortened form of synthetic divisionto test several values of r. In the table, thefirst column contains various values of r.The next three columns show thecoefficients of the depressed polynomial.The fifth column shows the remainder. Anyvalue of r that results in a remainder of zeroindicates that x r is a factor of thepolynomial. The factors of the originalpolynomial are x 4, x 2, and x 4. 16 32r12 41 2 80 31 1 137 210 160 111 17 15012 16 32113 13 45214 8 48315 1 3541680Look at the pattern of values in the last column. Notice that when r 1, 2, and 3, thevalues of f(x) decrease and then increase. This indicates that there is anx-coordinate of a relative minimum between 1 and 3.Example4 Determine the binomial factors of x3 7x 6.Method 1GraphingCalculatorTipThe TABLE feature canhelp locate integralzeros. Enter thepolynomial function asY1 in the Y menu andpress TABLE. Searchthe Y1 column to find 0and then look at thecorresponding x-value.r10Use synthetic division. 76 4 1 49 30 3 1 320 x 3 is a factor. 2 1 2 312 1 1 1 6120 10 761 11 60 x 1 is a factor.2 12 30 x 2 is a factor.Method 2 Test some values usingthe Factor Theorem.3f(x) x 7x 6f( 1) ( 1)3 7( 1) 6 or 12f(1) 13 7(1) 6 or 0Because f(1) 0, x 1 is a factor.Find the depressed polynomial.11 0 7611 61 1 60The depressed polynomial isx2 x 6. Factor the depressedpolynomial.x2 x 6 (x 3)(x 2)The factors of x3 x 6 are x 3, x 1, and x 2. Verify the results.The Remainder Theorem can be used to determine missing coefficients.Example5 Find the value of k so that the remainder of (x 3 3x 2 kx 24) (x 3) is 0.If the remainder is to be 0, x 3 must be a factor of x3 3x2 kx 24. So,f( 3) must equal 0.f(x) x3 3x2 kx 24f( 3) ( 3)3 3( 3)2 k( 3) 240 27 27 3k 240 3k 248 kReplace f( 3) with 0.The value of k is 8. Check using synthetic division. 311Lesson 4-33 30 8 24024 80 The Remainder and Factor Theorems225

C HECKCommunicatingMathematicsU N D E R S TA N D I N GFORRead and study the lesson to answer each question.1. Explain how the Remainder Theorem and the Factor Theorem are related.1 4 75511 252. Write the division problem illustrated by the syntheticdivision. What is the quotient? What is the remainder?8 10 23. Compare the degree of a polynomial and its depressed polynomial.Brittany tells Isabel that if x 3 is a factor of the polynomialfunction f(x), then f(3) 0. Isabel argues that if x 3 is a factor of f(x), thenf( 3) 0. Who is correct? Explain.4. You DecideGuided PracticeDivide using synthetic division.5. (x 2 x 4)(x 2)6. (x 3 x2 17x 15)(x 5)Use the Remainder Theorem to find the remainder for each division. Statewhether the binomial is a factor of the polynomial.GraphingCalculatorProgramFor a graphingcalculatorprogram thatcomputes thevalue of afunction visitwww.amc.glencoe.com7. (x 2 2x 15)(x 3)8. (x 4 x2 2)(x 3)Determine the binomial factors of each polynomial.9. x 3 5x 2 x 510. x 3 6x 2 11x 611. Find the value of k so that the remainder of (x 3 7x k)(x 1) is 2.12. Let f(x) x 7 x 9 x 12 2x 2.a. State the degree of f(x).b. State the number of complex zeros that f(x) has.c. State the degree of the depressed polynomial that would result from dividingf(x) by x a.d. Find one factor of f(x).13. GeometryA cylinder has a height 4 inches greater than the radius of its base.Find the radius and the height to the nearest inch if the volume of the cylinderis 5 cubic inches.E XERCISESDivide using synthetic division.PracticeA14. (x 2 20x 91)16. (x 4 x3 1)(x 7)15. (x 3 9x 2 27x 28)(x 2)17.18. (3x 4 2x 3 5x 2 4x 2)(x 1)(x 4 8x 2 16)19. (2x 3 2x 3)(x 3)(x 2)(x 1)Use the Remainder Theorem to find the remainder for each division. Statewhether the binomial is a factor of the polynomial.B20. (x 2 2)22. (x 4 24. (4x 32266x 2 (x 1) 8)4x 221. (x 5 32)(x 2 ) 2x 3)Chapter 4 Polynomial and Rational Functions(x 1)(x 2) x 6)23.(x 325.(2x 3 3x 2(x 2) x)(x 1)www.amc.glencoe.com/self check quiz

26. Which binomial is a factor of the polynomial x 3 3x 2 2x 8?a. x 1b. x 1c. x 2d. x 227. Verify that x 6 is a factor of x 4 36.28. Use synthetic division to find all the factors of x 3 7x 2 x 7 if one of thefactors is x 1.Determine the binomial factors of each polynomial.C29. x 3 x 2 4x 430. x 3 x 2 49x 4931. x 3 5x 2 2x 832. x 3 2x 2 4x 833. x 3 4x 2 x 434. x 3 3x 2 3x 135. How many times is 2 a root of x 6 9x 4 24x 2 16 0?36. Determine how many times 1 is a root of x 3 2x 2 x 2 0. Then find theother roots.Find the value of k so that each remainder is zero.37. (2x 3 x 2 x k)39. (x 3 18x 2 kx 4)l WoreaAponldRApplicationsand ProblemSolvingp li c a ti(x 1)(x 2)38. (x 3 kx 2 2x 4)(x 2)40. (x 3 4x 2 kx 1)(x 1)41. BicyclingMatthew is cycling at a speed of4 meters per second. When he starts down ahill, the bike accelerates at a rate of 0.4 meterper second squared. The vertical distance fromthe top of the hill to the bottom of the hill is125 meters. Use the equation d(t) v0t at 22to find how long it will take Matthew to ridedown the hill.42. Critical ThinkingDetermine a and b sothat when x 4 x 3 7x 2 ax b is dividedby (x 1)(x 2), the remainder is 0.43. SculptingEsteban is preparing to start an icesculpture. He has a block of ice that is 3 feetby 4 feet by 5 feet. Before he starts, he wantsto reduce the volume of the ice by shaving offthe same amount from the length, the width,and the height.a. Write a polynomial function to model the situation.b. Graph the function.3c. He wants to reduce the volume of the ice to of the original volume.5Write an equation to model the situation.d. How much should he take from each dimension?44. ManufacturingAn 18-inch by 20-inch sheet of cardboard is cut and folded tomake a box for the Great Pecan Company.20 in.a. Write an polynomial function to model thexxvolume of the box.xxb. Graph the function.c. The company wants the box to have a18 in.volume of 224 cubic inches. Write an equationto model this situation.xd. Find a positive integer for x.Lesson 4-3 The Remainder and Factor Theorems227

45. Critical ThinkingP(3 4i ) 0.Mixed ReviewFind a, b, and c for P(x) ax 2 bx c if P(3 4i ) 0 and46. Solve r 2 5r 8 0 by completing the square. (Lesson 4-2)47. Determine whether each number is a root of x 4 4x 3 x 2 4x 0.(Lesson 4-1)a. 2c. 2b. 0d. 448. Find the critical points of the graph of f(x) x 5 32. Determine whethereach represents a maximum, a minimum, or a point of inflection. (Lesson 3-6)49. Describe the transformation(s) that have taken place between the parentgraph of y x 2 and the graph of y 0.5(x 1)2. (Lesson 3-2)50. BusinessPristine Pipes Inc. produces plastic pipe for use in newly-builthomes. Two of the basic types of pipe have different diameters, wallthickness, and strengths. The strength of a pipe is increased by mixing aspecial additive into the plastic before it is molded. The table below showsthe resources needed to produce 100 feet of each type of pipe and theamount of the resource available each week.Pipe APipe BResourceAvailabilityExtrusion Dept.4 hours6 hours48 hoursPackaging Dept.2 hours2 hours18 hours2 pounds1 pound16 poundsResourceStrengthening AdditiveIf the profit on 100 feet of type A pipe is 34 and of type B pipe is 40, howmuch of each should be produced to maximize the profit? (Lesson 2-7)51. Solve the system of equations. (Lesson 2-2)4x 2y 3z 62x 7y 3z 3x 9y 13 2zy52. GeometryShow that the line segmentconnecting the midpoints of sides TR andT I is parallel to R I . (Lesson 1-5)T ( 2, 6)MR ( 7, 2)NOxI ( 2, 3)53. SAT/ACT PracticeIf a b and c0, which of the following are true?I. ac bcII. a c b cIII. a c b cA I onlyD I and II only228Chapter 4 Polynomial and Rational FunctionsB II onlyE I, II, and IIIC III onlyExtra Practice See p. A32.

In Example 2, the remainder is 0. Therefore, x 21 is a factor of x3 x 2. If f(x) 3x3 x2 2, then f( 1) ( 1) ( 1) 2 2 or 0. This illustrates the Factor Theorem, which is a special case of the Remainder Theorem. Use the Remainder Theorem to find the remainder when 2 x 3 3 x 2 x is divided by x 1. State whe

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