Engineering Mechanics- Morning Session Approximate 7%
Engineering Mechanics- Morning SessionApproximate 7%-10%Approximate 15 questions 30 minutes MAXReview 17 questions (taken from Lindeburg’s book, 2009)March 17th, 2014102/24/2014FEReview- ‐EngineeringMechanics- ‐UmutAkalp
0N(D)910N F FYXQUESTION1:FX 0 FX F cosθ XY 0 FY F cosθYSOLUTION:14) (500N )( ) 0 5213 FY (565N ) ( 2 ) (500N )( 5 ) F 0F 700N in(- ‐y)direcIon FX (565N ) ( Equilibrium!
YF2 300NMomentsQUESTION2:XOM 200N.m34SOLUTION:R nterofwheel.F3 m?(A)1.4m(B)1.6m(C)1.8m(D)2.2mM r FM Z xFY yFX MO 03 M O (200N m) (100N )( 5 )(2.5m) (300N )(2.5m) R(500N ) 0R 2.2m
lockwithamassof10kgwithdimensionsDxH,H 4DrestsonalevelsurfacewithcoefficientoffricIonμ ingoftheblockcanoccur?XSOLUTION: MO 0Dm M O ( 2 )(10kg)(9.81 s 2 ) h(20N ) 0Dm(10kg)(9.81 2 )52sh h 2.45D h D20N2
870.3cm4thenwhatistheareamomentinerIaabouttheX’- ‐axis?8cmXYX'XSOLUTION:I X I C Ad 2IX y 2 dA IY 2x 2 dA I X I X Ad XI X I C A(8cm)2 I C 3870.3cm 4 (60cm 2 )(8cm)2I X ' I C A(10cm)2 3870.3cm 4 (60cm 2 )(8cm)2 (60cm 2 )(10cm)2I X ' 6030.3cm 4
shownis245833cm4.Ifthecross- hecentroidalaxis?(A) 2.1x104cm4(B) 8.0x104cm4(C) 1.5x105cm4(D) 2.5x105cm4SOLUTION:I ' X I C,X Ad 2I C,X I X ' Ad 2 (245833cm 4 ) (250cm 2 )(30cm)2 20833cm 4 2.1 10 4 cm 4
CentroidsYQUESTION6:8cm5cmWhatarethex- ‐andy- ‐coordinatesofthecentroidofthearea?(A) 3.4cm;5.6cm(B) 3.5cm;5.5cm(C) 3.93cm;4.79cm(D) 4.00cm;5.00cm4cmdiameterA210cm7cm2cmby2cmA31cm1cmX
CentroidsSOLUTION:π (4cm)2A An (8cm)(10cm) (2cm)(2cm) 63.43cm 24π222(5cm)(80cm) ()(4cm)(7cm) (2cm)(4cm)yA c,n n4yC 4.79cmA63.43cm 2π222(4cm)(80cm) (5cm)()(4cm) (2cm)(4cm)xA c,n n4xC 3.93cm2A63.43cm
BC.(A) 0N(B) 1000N(C)(C) 1500N(T)(D) 2500N(T)
TrussMethodofJoints3000NSOLUTION:E MA 0 (3000N )(6.25) (3000N )(12.5m) (3000N )(5m) RCY (10m) (3000N )(15m)3000NBARCY 11625N(upward) FY 0 RAY (3)(3000N )(cos36.87O ) (2)(3000N ) 11625NRAY 1575N(upward)5400N1575N FXRAX 5400N(left)UsemethodofsecIonsYX 0 RAX (3)(3000N )(sin 36.87O ) M E 0 (5400N )(3.75m) (1575N )(5m) (3000N )(6.25m) BC(3.75m)BC 2500N
N(C)180N(D)240N2/s 5maYSOLUTION:ma F mgsin θ µ NF ?μ 0.25X25oF ma mgsin θ µ mg cosθF (5kg)(5F 56.8NmmmOO) (5kg)(9.81)sin25 (0.25)(5kg)(9.81)cos25s2s2s2
onofthediskonlyisvt,B A rω r(2π f )radrevA(12m 1.75m)(2π)(12)revmin 17.28m / svt,B A s60minYX
heryofthediskwithrespecttopointBisvt,Disk B rω r(2π f )radrev)(60)revmin 11.00m / ss60min(1.75m)(2πvt,B A ftwovelociIesvt,Disk A vt,Disk B vt,B Ammmvt,Disk A 17.28 11.00 28.28sssYAX
RotaIonalMoIonQUESTION10:ωAB rad/scw(D)12.5rad/scw5m
nvB 50m/s4mOB3mv ABω (5m)(10 rad ) 50m / sBAB3ωBCs4vCYXCω BCm50vBs 12.5rad / s(clockwise) OB 4m
α,ωRotaIonalMoIonQUESTION11:R ceisappliedatt 12s?(A)32.4cm(B)36.0cm(C)54.0cm(D)108cm1I mR 2 (0.5)(2kg)(0.3m)2 0.09kg.m 22radradα 3t (3)(12s) 36 2ssIαM 0 Fr Iα r Frad(0.09kg.m 2 )(36 2 )s 0.324m 32.4cmr 10N
/4(C)3g/7(D)3g/4ABCYXLL/4
eraIontangenIalacceleraIonofpointBcanbefound.1L1 17I C I CG md 2 ( )mL2 m( )2 mL2 ( ) ( )mL212412 16483LL3W 4W 4WL mgLM Fr ()() ()() C 424 244mgLMC 12g4α 7IC( )mL2 7L48L 12g 3gα t,B rα ( )() 4 7L7
12.4m/s(C)15.3m/s(D)18.6m/sSOLUTION:v'1 v'2 v'1 v'2 v' SIckingapercollisionv2 v1m1v1 m2 v2 (m1 m2 )v' ConservaIonofmomentume 0 mm) (5kg)(10 )ss 18.6 m(5kg) (2kg)s(2kg)(40v'
eaking?(A)0.05(B)0.25(C)0.35(A)0.65SOLUTION:mv 2FricIonalforcemustcounteracttheFf FC µ N ma m(rω ) centrifugalforcermv 2µ mg rkmm1h((80)(1000)())22vhkm 3600s 0.05µ mgr(9.81 2 )(1000m)s2
80kmSOLUTION:t v0 sin θggt 2v02 (sin θ )2 v02 (sin θ )2 v02 (sin θ )2y v0 (sin θ )t y0 22gg2gm(1250 )2 (sin 30O )2sy 19.9kmmm2(9.81 2 )(1000 )skm
4.6m/s(C)6.9m/s(D)8.9m/s
EnergySOLUTION:h I rod1L(sin 45O )2mL2 linearvelocitycanbefound.Iω 2mgh 21mL2 ω 2Omg( L sin 45 ) ()( )232m3(9.81 2 )(sin 45O )O3gsin 45radsω 4.56L1msradmmv rω (1m)(4.56) 4.56 4.6sss
VibraIonk 3.0N/cmm1 5kgm2 rm1?(A)9.81cm(B)16.4cm(C)19.6cm(A)26.2cm
VibraIonK .m1 5kgm2 3kg(5kg 3kg)(9.81F kδ W mg δ0 300δst,1 m1g k(5kg)(9.81Nmm)2s 0.2616m 26.16cmm)2s 0.1635m 16.35cmNmx0 δ0 δsr,1 26.16cm 16.35cm 9.81cm300
Engineering Mechanics- Morning Session Approximate 7%-10% Approximate 15 questions 30 minutes MA
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Mechanics and Mechanics of deformable solids. The mechanics of deformable solids which is branch of applied mechanics is known by several names i.e. strength of materials, mechanics of materials etc. Mechanics of rigid bodies: The mechanics of rigid bodies is primarily concerned with the static and dynamic
01 17-19 YEAR OLDS Session 1: Getting to know each other and getting to know yourself Session 2: Social and gender norms Session 3: Responsibility, choices and consent Session 4: Romantic relationships Session 5: Gender and human rights Session 6: Conception and contraception Session 7: Early and unintended pregnancy Session 8: Sexual health, STIs and HIV Session 9: Talking online
Engineering Mechanics Rigid-body Mechanics a basic requirement for the study of the mechanics of deformable bodies and the mechanics of fluids (advanced courses). essential for the design and analysis of many types of structural members, mechanical components, electrical devices, etc, encountered in engineering.
From my scientific perspective, a true „morning person‟ is someone for whom morning is their best time of day. „Morning people‟ wake up fairly easily, have more energy in the mornings and are more alert. Typically they have more energy and alertness in the morning than they do in the afternoon or evening. „Non-morning people‟, on the
Albert Woodfox, 68, has been in solitary confinement since his conviction in 1972 for the murder of a prison guard. He has always maintained his innocence. There is no physical evidence to link him to the crime; the conviction relied pri-marily on the testimony of an eye witness who received favours, including his re- lease, for cooperation. Albert’s conviction has been overturned three .
