GradeLevel/Course:&6th Lesson/UnitPlanName: Box&Plots .

structionalResources/Materials:Lesson1Ø Warm- ‐UpforeachstudentØ Posterpaperforvocabulary/demoboxplot,markersØ Ø Warm- ‐UpforeachstudentØ entØ 15penniesforeachgroupof3studentsØ 1plasticcupforeachsetofpenniesØ classsetofrulers(optional)Page 1 of 16MCC@WCCUSD 03/01/16

atdividead id- erquartile(Q3).Activity/Lesson:Lesson1Page 2 of 16MCC@WCCUSD 03/01/16

WarmUp/debriefVocabulary- ot- step- ‐by- f6thgraders:60,56,54,68,60,61,65,56,581. . 667683. ntowardsthecenter.54,56,56,58,60,60,61,65,684. 6364656667685. 54,56,56,58545556575859606162636465666768Page 3 of 16MCC@WCCUSD 03/01/16

6. 364656667687. 5758596061626364656667688. 758596061626364656667689. dthemaximum.10. nge,andinterquartilerange.1. Whatisthemedianofthedataset?602. Whatistherangeofthedataset?143. Whatistheinterquartilerange?7Page 4 of 16MCC@WCCUSD 03/01/16

upof3–4students.Warm- penniesinacentralplace,andthenre- n),20–25penniespercup.TheLesson:Warm- eoftoday’slesson.MakeGroupsof3- eets.Thestudentworksheetguidesthestudentstep- ‐by- eedindependently.Assessment:Thewarm- truction.Afterbothlessons,collectstudentbox- ‐plotstodetermineifanykeyconceptsneedtobere- ouldbereviewedwhole- Page 5 of 16MCC@WCCUSD 03/01/16

ovidedforyou,butyouwillneedtoaddyourownnumbers.1. Whatisthemedianofyourdataset?2. Whatistherange?3. Whatistheinterquartilerange?4. Isthedataskewedtotheleftortotheright?Page 6 of 16MCC@WCCUSD 03/01/16

dedforyou.1. Whatisthemedianofthedataset?2. Whatistherangeofthedataset?3. Whatistheinterquartilerange?4. Isyourdataskewedleftorright?Page 7 of 16MCC@WCCUSD 03/01/16

thenumber30onyourwork- rearenomorepenniesinthecup.2. lot.a. Findthemedian.Markthisvalueaboveyournumberline.b. ine.c. ine.d. keddatapoints.e. .Thesewillbetheendsofyourwhiskers.f. . h. Highfiveyourpartners.Then,answerthequestions.Page 8 of 16MCC@WCCUSD 03/01/16

Warm- ‐UpOne:BoxPlotsyA data set has these numbers:Find the median for a data set thathas these numbers:5, 7, 13, 2, 8, 7, 115, 7, 13, 2, 8, 7, 11What is the first step in findingthe median for this data set?xFind the median for this set ofdata:A student is finding the medianof a data set. She starts at themaximum and minimum, andstarts crossing out numbers:5, 8, 11, 13, 15, 1510, 12, 13, 17, 20, 25When she gets to the middle,there are two numbers left. Whatshould she do?Page 9 of 16MCC@WCCUSD 03/01/16

Warm- stherange?Usethisboxplottoanswerq uestions1- 16C.Page 10 of 16MCC@WCCUSD 03/01/16

Warm- ‐UpOne:AnswersyA data set has these numbers:5, 7, 13, 2, 8, 7, 11Find the median for a dataset that has these numbers:5, 7, 13, 2, 8, 7, 11What is the first step in findingthe median for this data set?After putting the numbers inorder: 2,5,7,7,8,11,13The first step would be to putI crossed off the numbersfrom each end until I foundthe median: 7.all the data points in order fromleast to greatest.xA student is finding the medianof a data set. She starts at themaximum and minimum, andstarts crossing out numbers:Find the median for this set of data:5, 8, 11, 13, 15, 1510, 12, 13, 17, 20, 25When she gets to the middle,there are two numbers left. Whatshould she do?5, 8, 11, 13, 15, 1511 13/2 12The median is 12.She should find the average ofthe two middle values:(13 17)/2 15Page 11 of 16MCC@WCCUSD 03/01/16

Warm- 2–10 thisboxplottoanswerq uestions1- 1,16C.BPage 12 of 16MCC@WCCUSD 03/01/16

Additional ResourcesParts of a Box PlotWeather Report for February 1stPage 13 of 16MCC@WCCUSD 03/01/16

Vertical box plots used to compare weather data in four different regions of Florida.Page 14 of 16MCC@WCCUSD 03/01/16

*Check-In Time!QuartilesAre the parts of this box plot labeled correctly?No. The lower quartile and upper quartile aremislabeled. Quartiles arethree points that divide thedata into four quarters.Interquartile Rangerange of this box plot?What is the interquartileQ1Q2!Q3Interquartile range is found by subtracting Q1 from Q3.23 - 16 7. Therefore, theinterquartile range is 7.Page 15 of 16MCC@WCCUSD 03/01/16

SkewHow can we describe the overall shape? Is the data skewed left,skewed right, or is it symmetrical? Why?The right half of the data is more widely distributed. Therefore, the data is skewedright.Page 16 of 16MCC@WCCUSD 03/01/16

Page 1 of 16 MCC@WCCUSD 03/01/16 GradeLevel/Course:&6th&& Lesson/UnitPlanName:!Box&Plots&Demystified& & Rationale/Lesson&Abstract:&Thisl