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Grade 11 Physics (30s)Midterm Practice examanswer Key

Grade 11 Physics (30s)Midterm Practice ExamAnswer KeyInstructionsThe final exam will be weighted as follows:Modules 1–6100%The format of the examination will be as follows:Part a: Multiple choice40 x 1 40 marksPart B: Fill-in-the-Blanks12 x 0.5 6 marksPart c: short explanations and diagramsPart d: Problems5 x 3 15 marks39 marksThe following instructions are meant to assist you when you are writing your midtermexamination. Please note the following instructions:nshow your work for the problems.ninclude directions with all vector answers.nround off answers to the correct number of significant digits.Midterm Practice exam answer Key3 of 43

Part a: Multiple choice (40 x 1 40 Marks)Circle the letter of the choice that best completes each statement.1. Those two quantities that are vectors area) distance and positionb) position and displacementc) displacement and speedAnswer (b)d) speed and velocityOutcome S3P.3.012. An object moves to the right 10.0 m from the starting point in a time of 1.0 s, then to theleft 20.0 m in a time of 3.0 s, and then to the right 5.0 m in a time of 1.0 s. The diagrambelow represents this motion.reference pointlll20.0 m10.0 ml5.0 mThe average velocity of the object over the whole time interval is best written asa) –1.0 m/sb) 0.8 m/sc) 1.2 m/sAnswer (a)d) 7.0 m/sOutcome S3P-3-014 of 43Grade 11 Physics

3. Of the position-time graphs below, the one that shows the highest speed in the negativedirection isa)dtb)dtc)dtd)dtAnswer (d)Outcome S3P-3-04Midterm Practice exam answer Key5 of 43

4. The following is a position-time graph.Position-Time Graph20.0Position (m)16.012.08.04.00.00.001.002.003.00Time (s)4.005.00The shape of the velocity-time graph that would best correspond with this position-timegraph isa)vtb)vtc) vtd)vtAnswer (a)Outcome S3P-3-046 of 43Grade 11 Physics

5. The following diagram shows a possible magnetic field line pattern between two polesof a bar magnet. Four positions a, b, c, and d, are indicated on the diagram.The positions that would most show the magnetic field vector pointing in the samedirection area) a and bb) a and dc) b and cAnswer (b)d) b and dOutcome S3P-4-176. The term “uniform motion” meansa) acceleration is constantb) speed is constantc) velocity is constantAnswer (c)d) displacement is constantOutcome S3P-3-047. The magnetic pole found in the northern hemisphere of our earth acts like thea) north pole of a bar magnet and the north pole of a compass needle would pointtowards itb) north pole of a bar magnet and the south pole of a compass needle would pointtowards itc) south pole of a bar magnet and the north pole of a compass needle would pointtowards itd) south pole of a bar magnet and the south pole of a compass needle would pointtowards itAnswer (c)Outcome S3P-4-20Midterm Practice exam answer Key7 of 43

8. Study the position-time graph pictured below and select the statement that is true.dPosition vs Timeta) The object’s speed is greatest during the last segment.b) The object’s acceleration is greatest during the last segment.c) The object’s average acceleration is zero.d) The object travels a greater distance in the first segment than in the last segment.Answer (a)Outcome S3P-3-049. Contact forces such as the force of friction and the force of a glove on a punching bag areexamples ofa) gravitational forceb) electromagnetic forcec) strong nuclear forceAnswer (b)d) weak nuclear forceOutcome S3P-3-0810. If an object is already moving and the sum of all the vector forces on a mass is zero, thenthe object willa) move at a constant speed in a straight lineb) accelerate at a constant rate in a straight linec) come to restAnswer (a)d) increase its amount of inertiaOutcome S3P-3-1111. A net force acts on a mass of 8.00 kg causing it to move from rest to a speed of 10.0 m/sin a time of 5.00 s. The net force must have a magnitude ofa) 8.00 Nb) 16.0 Nc) 40.0 NAnswer (b)d) 80.0 NOutcome S3P-3-138 of 43Grade 11 Physics

12. Two forces are acting on a mass of 20.0 kg. One force is to the right at 400.0 N while theother force is to the left at a magnitude of 600.0 N. The acceleration of the wagon isa) –50.0 m/s2b) –10.0 m/s2c) 10.0 m/s2d) 50.0Answer (b)m/s2Outcome S3P-3-1113. A free-body diagram for a ball in free fall in a vacuum isa)vFFvFgb)vFFvFgc)vFgd)vFgAnswer (d)Outcome S3P-3-12Midterm Practice exam answer Key9 of 43

14. An object is being pulled to the right. The object is accelerating to the right, and frictionis present. The correct free-body diagram for this situation d)vFFlvFgAnswer (a)Outcome S3P-3-1215. Which of the following fundamental forces is the strongest?a) strong nuclearb) electrostaticc) weak nuclearAnswer (a)d) They are equally strong.Outcome S3P-3-0810 of 43Grade 11 Physics

16. The diagram below shows a horseshoe magnet with the north pole and south pole asindicated. A wire is placed between the poles and the current moves as shown.SlNcurrent ( )The direction of the force on the wire isa) up out of the pageb) down into the pagec) towards the interior of the magnet (west)Answer (c)d) towards the outside of the magnet (east)Outcome S3P-3-0817. The gravitational field can be defined as thea) region of space around a mass where another mass experiences a forceb) acceleration due to gravity which is equal to approximately 9.80 m/s2 for our Earthc) force divided by the mass for an object in free falld) the amount of the contact force between a mass at rest on the surface of the Earth andthe EarthAnswer (a)Outcome S3P-4-01Midterm Practice exam answer Key11 of 43

18. A straight wire has a current of 2.0 A passing through it. The wire is 10.0 cm long. Thewire, which is oriented so that it is perpendicular to a magnetic field, is 5.0 T.wire of length LIBThe magnitude of the force on the wire isa) 0.0 Nb) 1.0 Nc) 1.0 x 101 Nd) 1.0 x102NAnswer (b)Outcome S3P-4-28 19. The value of the acceleration due to gravity, g, can be determined experimentally byrecording and analyzing the time and position of a ball while it isa) rolling freely across a horizontal tableb) pulled across a horizontal table by a constant forcec) dropped in free fallAnswer (c)d) pushed upwards by a constant forceOutcome S3P-4-0720. When an object has reached terminal velocity, the shape of the line in a velocity-timegraph isa) horizontalb) straight and oblique with a positive slopec) straight and oblique with a negative slopeAnswer (a)d) curving upwardsOutcome S3P-4-0921. The coefficient of friction can be defined as the ratio of thea) force of gravity over the force of frictionb) force of friction over the normal forcec) normal force over the force of gravityAnswer (b)d) force of gravity over the applied forceOutcome S3P-4-1012 of 43Grade 11 Physics

22. How much would a 60.0 kg person weigh on the moon where the gravitational fieldstrength has a magnitude of 1.60 N/kg?a) 60.0 kgb) 96.0 Nc) 98.0 kgAnswer (b).0d) 98.0 NOutcome S3P-4-0423. Two magnetic fields are acting on a 2.0 m long wire carrying a current of 8.0 A to theeast. One of the magnetic fields is acting vertically downward into the paper. It has amagnitude of 5.0 x 10–5 T. A second magnetic field is acting at 4.0 x 10–5 T to the south.The magnitude of the net force on the wire isa) 1.0 x 10–6 Nb) 4.8 x 10–4 Nc) 1.0 x 10–3 Nd) 3.8 x10–2Answer (c)NOutcome S3P-4-28, S3P-2h24. Objects onboard an orbiting space station appear to be “floating” becausea) they’re in the vacuum of spaceb) they’re weightlessc) they’re outside Earth’s gravitational pullAnswer (d)d) they’re falling together with the space stationOutcome S3P-4-0525. If a positive charge A is twice as large as a positive charge B, we could show this bydrawinga) the field lines in the opposite direction for one of the chargesb) the same number of field lines as B but shorterc) twice as many field lines for charge AAnswer (c)d) half as many field lines for charge AOutcome S3P-4-1526. If we were to compare the field lines for the gravitational situation to the electricsituation, we would find that the electric field line pattern that is identical to thegravitational pattern around the Earth occurs when there isa) a neutral chargeb) a combination of positive and negative chargesc) one positive chargeAnswer (d)d) one negative chargeOutcome S3P-4-15Midterm Practice exam answer Key13 of 43

27. The diagram below shows an electric field line pattern for two charges.This is an electric field line pattern for twoa) negative chargesb) positive chargesc) neutral chargesAnswer (a)d) opposite chargesOutcome S3P-4-1514 of 43Grade 11 Physics

28. The diagrams below show a positively charged plate and a negative point charge. Theelectric field line pattern for this situation is best shown bypositive platea)lnegative point chargepositive plateb)lnegative point chargepositive platec)lnegative point chargepositive plated)lnegative point chargeAnswer (d)Outcome S3P-4-15Midterm Practice exam answer Key15 of 43

29. The negative charge, –q1, to the left of point P, creates an electric field, E1 , of magnitude10.0 N/C at position P. The positive charge to the right of point P, q2, creates an electricfield, E2 , of magnitude 25.0 N/C at position P.lq1Plq2The directions of the electric fields at position P area) both to the westb) both to the east c) E1 to the east and E2 to the west d) E1 to the west and E2 to the eastAnswer (a)Outcome S3P-4-16 30. The negative charge, –q1, to the west of point P, creates an electric field, E1 , of magnitude10.0 N/C at position P. The positive charge, q2, to the south of point P, creates an electricfield, E2 , of magnitude 25.0 N/C at position P.lq1Plq2The direction of the total electric field at position P isa) 68.2 S of Wb) 68.2 N of Wc) 21.8 S of WAnswer (b)d) 21.8 N of WOutcome S3P-4-16, S3P-0-2h31. In a Millikan apparatus, a sphere of mass 4.0 x 10–15 kg is stationary in an electric fieldwhose intensity is 2.00 x 104 N/C. The top plate is positive. The magnitude of the chargeon the sphere must bea) 2.0 x 10–18 Cb) 1.3 x 104 Cc) 5.1 x 1017 CAnswer (a)d) 3.2 x 1036 COutcome S3P-4-1816 of 43Grade 11 Physics

32. A ferromagnetic material is placed in a strong magnetic field that points from the left tothe right.The domains in the material pointa) in the up directionb) in the down directionc) to the rightAnswer (c)d) to the leftOutcome S3P-4-1933. State the number of significant digits in 0.0089076500a) 8b) 9c) 10Answer (a)d) 11Outcome S3P-0-2d34. The correct answer for the product of 6.9530 x 0.07843 isa) 0.5453b) 0.54532c) 0.545323Answer (a)d) 0.5453238Outcome S3P-0-2d35. The correct answer for the sum of 18.3 6.92 2.0084 isa) 27.2282b) 27.22c) 27.2Answer (c)d) 27.228Outcome S3P-0-2d36. Which of the following is NOT a mode of representation used in physics?a) visual modeb) graphical modec) diagram modeAnswer (c)d) symbolic modeOutcome S3P-2-02Midterm Practice exam answer Key17 of 43

37. The slope of a chord on a position-time graph represents which of the followingquantities?a) average accelerationb) average velocityc) average displacementAnswer (b)d) average distanceOutcome S3P-3-0538. Which of the following is not a characteristic of the components of a vector?a) The components are parallel to each other.b) The components add to give the vector.c) The components are independent of each other.d) The magnitudes of the components can be added using the Theorem of Pythagoras.Answer (a)Outcome S3P-0-2h39. What is the displacement of a cyclist who starts at highway marker 3 km and ends atmarker –7 km? Consider positive numbers as representing positions east of the centre oftown.a) l0 km [W]b) 10 km [E]c) 4 km [W]Answer (a)d) 4 km [E]Outcome S3P-3-0240. What is the magnitude of the net force acting on an object if the following forces are eachpulling horizontally on the object: force one 5.2 N [E] and force two 6.8 N [S]?a) 12.0 Nb) 1.6 Nc) 8.6 NAnswer (c)d) 73 NOutcomes S3P-0-2h, S3P-3-1218 of 43Grade 11 Physics

Part B: Fill-in-the-Blanks (12 x 0.5 6 Marks)Using a term from the word bank provided below, complete each of the followingstatements. Some of the terms will not be used and some of the terms may be used morethan hordnegativetangentexternalnormalvelocityfree fallpositionweightgravitational field intensity1. The gravitational field intensity is the quotient of the gravitational force and themagnitude of the test mass at a given point in the field.2. Any force exerted by an object that is not part of the system on an object within thesystem is known as a(n) external force.3. Mass is amount of matter present in an object.4. The length of a path travelled by an object is called the distance.5. The resultant is the vector representing the sum of two or more vectors.6. The rate of change of position is known as velocity.7. The normal force is a force that acts in a direction perpendicular to the common contactsurface between two objects.8. The location of an object as measured from the origin of a frame of reference is known asposition.9. The tendency of an object to resist changes in its state of motion is called inertia.10. The direction of the electric field at a given point in space is determined by the directionof the electric force acting on a charge with a positive sign.11. A(n) tangent is a line that intersects a curve at only one particular point.12. Free fall describes the situation in which the only force acting on an object is the force ofgravity.Midterm Practice exam answer Key19 of 43

Part c: short explanations and diagrams (5 x 3 15 Marks)Answer any five (5) of the following questions. Be sure to indicate clearly which fivequestions are to be marked.Outcome S3P-3-011.Distinguish between vectors and scalars. Give an example of each.Answer:The scalar is a quantity with magnitude only. An example would be a time interval (5 s).The vector is a quantity with magnitude and direction. An example would bedisplacement or velocity (5 m/s [east]).Outcome S3P-3-042.Indicate whether you would use slope or area to convert between the following graphs:a) velocity to positionb) velocity to accelerationc) position to velocityAnswer:a) uses areab) uses slopec) uses slopeOutcome S3P-3-133.Using Newton’s Laws of Motion, explain the following:a) A child is sitting on a motionless toboggan. The rope of the toboggan is given a sharptug forward. The child falls off the back of the toboggan.Answer:The child sitting at rest has inertia of rest. This is Newton’s First Law: Objects at restremain at rest. The toboggan is pulled out from under the child by the force. This isNewton’s Second Law: An object accelerates in the direction of the unbalanced force.b) A person kicks a football. The person breaks his toe while kicking the ball.Answer:This is Newton’s Third Law: For every action force, there is an equal but oppositereaction force. The action force is the foot kicking the ball. The reaction force isexerted by the ball on the foot. This force breaks the toe.20 of 43Grade 11 Physics

Outcome S3P-1-214.Using the Domain Theory of Magnetism, explain the following.a) When placed in a strong magnetic field, a bar of iron becomes a bar magnet. Whenthe field is removed, the piece of iron is no longer a bar magnet.Answer:When the bar of iron is placed in a strong magnetic field, the magnetic domainswithin the piece of iron align themselves with the magnetic field. The bar of iron thenacts like a bar magnet. When the magnetic field is removed, the magnetic domainsreturn to their original random arrangement. The piece of iron is no longer a barmagnet.b) Over a period of years, the steel girders in a building become magnetized.Answer:Over a period of years, the magnetic domains within the steel girders alignthemselves with the Earth’s magnetic field, thus becoming magnetized.Outcome S3P-4-035.Describe two methods of measuring the gravitational field at the Earth’s surface.Answer:The first method involves using a scale to find the weight of an object of known mass.Then the gravitational field is calculated as the ratio of the force of gravity over the mass.The second method involves allowing a dense, heavy object to fall freely. Theacceleration of this object is measured and equals the gravitational field at that point.Midterm Practice exam answer Key21 of 43

Outcome S3P-4-056.An astronaut circling the Earth in a space shuttle at an altitude of 400 km is weightless.Do you agree or disagree with this statement? Justify your choice.Answer:This astronaut is not truly weightless but only apparently weightless. To be trulyweightless, the gravitational field at that point must be 0 N/kg. At 400 km altitude, thegravitational field is still quite large so the astronaut still has weight. He appears to beweightless because he is really falling along with his surroundings.Outcome S3P-4-157.Give three bits of information given by a pattern of electric force field lines.Answer:The pattern of force field lines has the lines closer together where the force field isstronger.The direction of the field at any point points in a direction that is tangent to the forcefield line.Electric force field lines begin on negative charge and end on positive charge.Electric field lines meet the surface of a conductor at a 90 angle.22 of 43Grade 11 Physics

Outcome S3P-4-158.Draw the electric field arounda) a negative point charge. (1 mark)Answer:-b) a dipole made of a positive point charge and a negative point charge. (2 marks)Answer:Midterm Practice exam answer Key23 of 43

Outcome S3P-4-279.Will the two solenoids given below attract each other or repel each other? Explain youranswer.llllllllllllllllllAnswer:The solenoid on the left will have the north end of the phantom bar magnet on the leftand the south pole on the right (near the centre).The solenoid on the right will have the south end of the phantom magnet on the left side(near the centre).Since the two south poles are closest together, the solenoids will repel each other.24 of 43Grade 11 Physics

Part d: Problems (39 Marks)Answer Question 1 plus any five (5) other problems.Outcome S3P-3-04, S3P-3-05Use the velocity-time graph below to answer the questions that follow.Velocity-Time Graph105Velocity (m/s)1.0-5010Time (seconds)2030a) Fill in the table for position-time data, assuming the object starts at 5.0 m. Graphthese data on a sheet of graph paper. (5 2 marks)Answer:Time Interval(seconds)Displacement (m)Find areaPosition at End of the Interval(m)vPos2 Pos1 d0—5½(a b)h ½(–2 (–4))(5) –15( 5.0) (–15) –1010–15½bh ½(5)( 6) 15(–20) ( 15) –525–30½(a b)h ½( 6 – ( 2))(5) 2005–1015—25½bh ½(5)(–4) –10lw (10)( 6) 60 5.0(–10) (–10) –20(–5) ( 60) 55( 55) ( 20) 75Midterm Practice exam answer Key25 of 43

Position-Time GraphlPosition (metres)500l0ll1020Time (seconds)30b) Calculate the average velocity. (1 mark)Answer:The average velocity is the slope of the chord on a position-time graph joining theinitial position (0 s, 5 m) to the final position (30 s, 75 m).rise 75 m 5 m 70 m vavg 2.3 m/s30 s 0 s30 srunc) Calculate the average acceleration. (1 mark)Answer:The average acceleration is the slope of the chord on a velocity-time graph joining theinitial velocity (0 s, –2 m/s) to the final position (30 s, 2 m/s).rise 2 m /s 2 m/s 4 m/s 0.13 m/s 2 aavg 30 s 0 s30 srun26 of 43Grade 11 Physics

Answer any five (5) of the remaining questions. Be sure to indicate clearly whichquestions you are submitting for evaluation.2.A car travelling at 24.2 m/s decelerates at the rate of 2.10 m/s2. CalculateOutcome S3P-3-062va) the time required by the car to stop. (2 marks)Answer:Let to the right be positive.Given: Initial velocityAccelerationFinal velocityUnknown: Time intervalEquation:Substitute and solve: v1 24.2 m/s a 2.10 m/

Midterm Practice exam answer Key 3 of 43 Grade 11 P hysics (30s) M ˇ P a ˇ E a A ˆ K I c i The final exam will be weighted as follows: Modules 1 –6 100% The format of the examination will be as follows: Part a: Multiple choice 40 x 1 40 marks Part B: Fill-in-the-Blanks 12 x 0.5 6 marks

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