XMUT315 Control Systems Engineering Note 3: Physical Systems Modelling

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XMUT315 Control Systems EngineeringNote 3: Physical Systems ModellingTopics Modelling physical systems. Lumped parameters models. LTI models. Linearization. Modelling aspects and process. Modelling mechanical systems. Modelling electrical systems. Modelling electromechanical systems.1. Modelling Physical SystemsModelling the physical systems is required in control system engineering to represent the system for itsanalysis and design.1.1. How to Model Physical SystemsOften to model a physical system we employ a scaled physical model that is a proportional to the actualmodel. As illustrated in the figure below, a scaled down version of a car is used to model the car when itundergo air flow experiment in a given car manufacturer’s laboratory.With the miniature model, it is easier to analyse and design the air flow and the model might be able tofit the limited space of the wind tunnel laboratory. But, beware that this approach will not be ascomprehensive as the experiment with the actual car.

Note 3: Physical Systems ModellingFigure 1: Modelling of a physical system with scaled physical modelOn the other hand, to represent the physical system in addition to scaled model, we often usemathematical and numerical models. Mathematical model is described as function and variable inmathematical equation. Whereas, numerical model is represented as a set of numbers to describesystem characteristic and behaviour.1.2. Modelling of Physical SystemsWe also could develop mathematical models, i.e. ordinary differential equations that describe therelationship between input and output characteristics of a system. These equations can then be used toforecast the behaviour of the system under specific conditions. All systems can normally beapproximated and modelled by one of several models, e.g. mechanical, electrical, thermal, or fluid. Wealso find that we can translate a system from one model to another to facilitate the modelling.- Figure 2: Translation of non-linear model to linear modelXMUT315 - Note 3 - 2

Note 3: Physical Systems Modelling1.3. Lumped Parameter ModelsLumped parameter models apply the use of standard laws of physics and break a system down into anumber of building blocks.Figure 3: Lumped parameter model of a walking robotEach of the parameters (property or function) is considered independently. Furthermore, the analysisand design will be conducted on these parts. The figure above shows lumped parameter modeldecomposition of walking robot, whereas the figure given below represents a lumped parameter modelfor a connection bridge for footpath.Figure 4: Lumped parameter model of a bridgeXMUT315 - Note 3 - 3

Note 3: Physical Systems ModellingThe bridge given in the figure above is a millennium bridge that was notoriously wobbly when it wasinitially constructed, see further for its details: http://www.youtube.com/watch?v eAXVa XWZ81.4. Linear Time Invariant ModelsFor modelling of the systems, to simplify the analysis and design, we often assume the property oflinearity for these models. A linear system will have two properties: Superposition – evaluate parts of the system and conclude the characteristics and behaviour ofthe overall system as consisted of those of these parts. Homogeneity (uniformity of material) – for a given system, there is uniform characteristics andbehaviour of the same part of the system.Then, this allows us to use standard mathematical operations to simplify our models.Figure 5: Superposition of several wavesThe figure above shows the superposition of several waves to make up a complex signal. The overallcharacteristics and behaviour of this signal is evaluated based on the characteristics and behaviour of itsindividual components that constitute itself.The figure shown below illustrates that the characteristic and behaviour of a given damper is uniformthroughout itself. When the damper is stretched, it will stretch uniformly, rather than stretchingdifferently at different parts like illustrated in the figure.XMUT315 - Note 3 - 4

Note 3: Physical Systems ModellingFigure 6: Damper with uniform (left) and non-uniform (right) materialsAssuming that the system is time-invariant, constants stay constant in the time-scales of our model. Weacknowledge that proportionality between variables does not change throughout the life span of thesystem. Note that our shock absorbers do not wear out in our car suspension model as it often happensin practice!Figure 7: Worn out in the shock absorbers1.5. LinearisationLinearisation is finding the linear approximation to a function at a given point. The linear approximationof a function is the first order Taylor expansion around the point of interest.In the study of dynamical systems, linearisation is a method of choice for assessing the local stability ofan equilibrium point of a system of nonlinear differential equations or discrete dynamical systems.Intuitively, linearisation is performed with tangent or Taylor series:XMUT315 - Note 3 - 5

Note 3: Physical Systems Modelling d 2 y x x0 dy y f x0 x x0 2 .2! dx x0 dx x0Linearisations of a function are lines e.g. usually lines that can be used for purposes of calculation.Linearisation is an effective method for approximating the output of a function 𝑦 𝑓(π‘₯) at any π‘₯ π‘Ž based on the value and slope of the function at π‘₯ 𝑏, given that 𝑓(π‘₯) is differentiable on [π‘Ž, 𝑏] (or )[𝑏, π‘Ž] and that π‘Ž is close to 𝑏. In short, linearization approximates the output of a function near π‘₯ π‘Ž.A finite number of terms will give an approximation of the function e.g. the first two terms will give alinear approximation.For example, consider 𝑓(π‘₯) 2π‘₯ 5π‘₯ 3 . It has an operating point π‘₯ 1, where 𝑓(π‘₯) 10 17π‘₯.We model the spring force as 𝑓(π‘₯) 10 17π‘₯ around the point π‘₯ 1.0 and the linearized springforced constant would be given by 𝑑𝑓/𝑑π‘₯ 17 N/m.2. Components of Physical ModellingOnce the physical system or entity is model, we need to represent it for its analysis and design. Incontrol system engineering, the most common approach is to model it in the block diagram modelling.2.1. SignalsIn block diagram modelling, components are connected together by signals. Signals have many differentforms depending on their characteristics and behaviours as shown in the figure below. Signals must alsohave direction and name when they are modelled in the clock diagram modelling.Figure 8: Several examples of common signal in control systemXMUT315 - Note 3 - 6

Note 3: Physical Systems ModellingSignals will continue to flow until interrupted. In the modelling, signals and components are consideredideal. We add other signals and components to alter the signals. Often, during modelling, we wish toknow how the output signal varies with an input signal for a fixed (invariant) system as illustrated in thefigure below. Also, we may plot two signals against each other invariant of time (system relationship).Figure 9: Input and output signals2.2. ConstantsSystem constants are considered to be time invariant for the given system. For a spring example given inthe figure below, the constant of a spring is unique for that particular spring. We consider a differentsystem as the spring has been changed. However, the analysis stays the same.Figure 3.10: Spring system with different spring constant valuesXMUT315 - Note 3 - 7

Note 3: Physical Systems Modelling2.3. DifferentiationConsider differentiation as alternative method for modelling. Level of the water, 𝐿, changes because ofthe flow of liquid. Mathematically, change of 𝐿 with time is 𝑑𝐿/𝑑𝑑. In fact, the change in 𝐿 isproportional to flow, 𝐹:𝑑𝐿1 ( )𝐹𝑑𝑑𝐢and𝐹 𝐼 𝐿𝑅Flow is related to difference in levels, thus𝑑𝐿1 𝐼 𝐿𝐼 𝐿) ( )(𝑑𝑑𝐢𝑅𝐢𝑅Where: 𝐢𝑅 is the time constant of the system, 𝑇.Note: the above case is a differential equation. It has the differential of 𝐿 being a function including 𝐿.2.4. Differentiation: SlopesConsider the graph of level or height of the water (𝐿) as shown in the figure given below. At any instantof time, we can see value of 𝐿 observed in the graph. The change in 𝐿 is the slope of the graph, whichvaries with time. Initially the slope is steep (high value), then less, and becoming finally less.LtFigure 11: Slopes in graphBut, the flow is initially high, then less, then finally less. Thus, slope of 𝐿 is like 𝐹, but slope is change of𝐿. In fact, 𝐹 is proportional to derivate of 𝐿 with time.2.5. Integration: AreaXMUT315 - Note 3 - 8

Note 3: Physical Systems ModellingThe reverse process of differentiation is integration. Its graphical interpretation is the area under agraph. Consider the flow graph of the water level of two tanks: the area at different times is shown as inthe figures given below.FFFttFigure 12: Integration of area under a graphAfter a short time, the area is as shown in the figure on the left. Later, area has grown, but by less, etc.Consider the height of water in the tank in the right figure. Thus, 𝐿 like area under 𝐹 e.g. 𝐹 𝑑𝑑. Thewater level, 𝐿 is proportional to integral of 𝐹 with time. In fact, for this system, we have:𝑑𝐿1 ( )𝐹𝑑𝑑𝐢L 1 𝐹 𝑑𝑑CThe flow, 𝐹 is differential of the level 𝐿 and 𝐿 is integral of 𝐹. Differentiation and integration areopposites.Note: here they are used to model a water system. It can also model electronic circuits, mechanicalsystems, motors, etc. In fact, the differential equation has the same form, and hence the sameexponential response as that for many systems.There are analogies between water systems and electronics: pipe like a resistor, tank like a capacitor.Also, for thermals, walls have thermal resistance and rooms have thermal capacity.3. Mechanical System ModellingSimple mechanical systems can be represented as models from their standard components.3.1. Mechanical ComponentsWe know that distance (π‘₯(𝑑)) is related to velocity (𝑣(𝑑)) is related to acceleration (π‘Ž(𝑑)) throughdifferentiation.XMUT315 - Note 3 - 9t

Note 3: Physical Systems Modelling𝑑π‘₯(𝑑)𝑑π‘₯(𝑑)𝑑𝑣 𝑑 ( 𝑑𝑑 ) 𝑑 2 π‘₯(𝑑)π‘₯(𝑑) π‘₯(𝑑); 𝑣(𝑑) ; π‘Ž(𝑑) 𝑑𝑑𝑑𝑑𝑑𝑑𝑑𝑑 2If we derive the model from first principles, it gets messy writing 𝑑/𝑑𝑑 all the time. Therefore, we useLaplace transform and will write in term of β€˜π‘ β€™ instead.𝑋(𝑠) 𝑋(𝑠);𝑉(𝑠) 𝑠𝑋(𝑠);𝐴(𝑠) 𝑠𝑉(𝑠) 𝑠 2 𝑋(𝑠)Note: both with respect to the variable.Figure 13: Standard basic mechanical components3.2. Modelling Mechanical SystemsFor the above mechanical system: We assume the mass is displaced by π‘₯(𝑑) toward the right. Note that taking into consideration the zero initial condition, just like the spring (with springconstant, π‘˜), the damper (with damper constant, 𝑓𝑣 ) will also oppose the force. Thus, only the applied force points to the right. All other forces impede the motion and act to oppose it e.g. the spring, damper, and the forcedue to acceleration point to the left.XMUT315 - Note 3 - 10

Note 3: Physical Systems ModellingFigure 14: Mechanical system of spring-damper-mass system3.3. Model of Mechanical SystemsWrite the differential equation of motion using Newton's law to sum to zero all of the forces that exist inthe given mechanical system.𝑑 2 π‘₯(𝑑)𝑑π‘₯(𝑑)) π‘˜π‘₯(𝑑) 𝑓(𝑑)π‘š() 𝑓𝑣 (2𝑑𝑑𝑑𝑑Taking the Laplace transform, assuming zero initial conditions, the equation above becomes:π‘šπ‘  2 𝑋(𝑠) 𝑓𝑣 𝑠𝑋(𝑠) π‘˜π‘‹(𝑠) 𝐹(𝑠)As a result, the transfer function of the given mechanical system is:𝐺(𝑠) 𝑋(𝑠)1 2𝐹(𝑠) π‘šπ‘  𝑓𝑣 𝑠 π‘˜4. Electrical Systems ModellingLike mechanical systems, electrical systems can be modelled from their standardised components.4.1. Electrical ComponentsWe know that to find the reactance of electrical devices such inductor and capacitor requires integrationand differentiation respectively. Voltage across resistor:𝑣𝑅 (𝑑) 𝑅𝑖(𝑑) Voltage across capacitor:XMUT315 - Note 3 - 11

Note 3: Physical Systems Modelling𝑣𝐢 (𝑑) 1 𝑑 𝑖(𝑑)𝐢 0Voltage across inductor:𝑑𝑖(𝑑))𝑣𝐿 (𝑑) 𝐿 (𝑑𝑑By applying Laplace transform, we have the following: Voltage across resistor:𝑉𝑅 (𝑠) 𝑅𝑖(s) Voltage across capacitor:1𝑉𝐢 (𝑠) ( ) 𝑖(𝑠)𝑠𝐢 Voltage across inductor:𝑉𝐿 (𝑠) 𝑠𝐿𝑖(𝑠)Note: both components and their Laplace transforms are with respect to the variable.Figure 15: Standard basic electrical components4.2. Modelling Electrical SystemsXMUT315 - Note 3 - 12

Note 3: Physical Systems ModellingFor the electrical system as shown above: It is a series RLC circuit. Assume in this case that the capacitor voltage as the output and the applied voltage as theinput. Assume zero initial conditions (no prior conditions before modelling existed).Figure 16: Electrical system of RLC circuit4.3. Model of Electrical SystemsSumming the voltages around the loop, assuming zero initial conditions, yields the integral-differentialequation for this network as:𝑑𝑖(𝑑)1 𝑑) 𝑅𝑖(𝑑) 𝑖(𝜏)π‘‘πœ 𝑒(𝑑)𝐿(𝑑𝑑𝐢 0Changing variables from current to charge using 𝑖(𝑑) π‘‘π‘ž(𝑑)/𝑑𝑑 yields:𝑑 2 π‘ž(𝑑)π‘‘π‘ž(𝑑)1) ( ) π‘ž(𝑑) 𝑒(𝑑)𝐿() 𝑅(2𝑑𝑑𝑑𝑑𝐢From the voltage-charge relationship for a capacitor:π‘ž(𝑑) 𝐢𝑣𝐢 (𝑑)Substituting Eq. (2) into Eq. (1) yields:𝑑 2 𝑣𝐢 (𝑑)𝑑𝑣𝐢 (𝑑)) 𝑣𝐢 (𝑑) 𝑒(𝑑)𝐢() 𝑅𝐢 (2𝑑𝑑𝑑𝑑Taking the Laplace transform assuming zero initial conditions, rearranging terms, and simplifying yields:XMUT315 - Note 3 - 13

Note 3: Physical Systems Modelling(𝐿𝐢𝑠 2 𝑅𝐢𝑠 1)𝑉𝐢 (𝑠) 𝐸(𝑠)Solving for the transfer function, 𝑉𝐢 (𝑠)/𝑉(𝑠), we obtain:𝑉𝐢 (𝑠)1/𝐿𝐢 𝐸(𝑠) 𝑠 2 (𝑅 ) 𝑠 1/𝐿𝐢𝐿5. Electromechanical System ModellingSince it is consisted of mechanical and electrical systems, modelling of electromechanical system couldtypically be performed using the standardised components of the mechanical and electrical systems5.1. Modelling Electromechanical SystemFor the electromechanical system as given below: Motor is used to drive a mechanical load (𝐽𝐿 ) pushing a damper (𝐷𝐿 ). Motor has inertia (π½π‘Ž ) and damping factors (π·π‘Ž ). Motor characteristics requiring electrical constants (e.g. 𝐾𝑑 /π‘…π‘Ž and 𝐾𝑏 ).Figure 17: Electromechanical system of a DC motor with loadDetermine the block diagram for electromechanical system and then derive its transfer functionequation, preferably in terms of πœƒπ‘š (𝑠) and πΈπ‘Ž (𝑠) e.g. the speed of the given DC motor (πœƒπ‘š (𝑠)) isdetermined from the voltage applied across its armature (πΈπ‘Ž (𝑠)).XMUT315 - Note 3 - 14

Note 3: Physical Systems Modellingπœƒπ‘š (𝑠)𝐾𝑑 /(π‘…π‘Ž π½π‘š ) πΈπ‘Ž (𝑠) 𝑠 [𝑠 1 (𝐷 𝐾𝑑 𝐾𝑏 )]π½π‘š π‘šπ‘…π‘ŽKnowing inertia (π½π‘š ) and damping factor (π·π‘š ) of the motor is:𝑁1 2π½π‘š π½π‘Ž 𝐽𝐿 ( )𝑁2𝑁1 2π·π‘š π·π‘Ž 𝐷𝐿 ( )𝑁2We could obtain the electrical constants, 𝐾𝑑 /π‘…π‘Ž and 𝐾𝑏 from the torques-speed curve.Figure 18: Graph of torque vs. speed of a DC motor with loadXMUT315 - Note 3 - 15

Note 3: Physical Systems Modelling XMUT315 - Note 3 - 2 Figure 1: Modelling of a physical system with scaled physical model On the other hand, to represent the physical system in addition to scaled model, we often use mathematical and numerical models. Mathematical model is described as function and variable in mathematical equation.

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